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olga2289 [7]
2 years ago
10

Calculator Reference

Chemistry
1 answer:
kipiarov [429]2 years ago
3 0

Answer:

CO₂ + 4 H₂S + O₂ ---> CH₂O + 4 S + 3 H₂O

Explanation:

The unbalanced equation looks like this:

CO₂ + H₂S + O₂ ---> CH₂O + S + H₂O

Below is the amount of each element on each side of the reaction.

Reactants:

    > 1 carbon, 2 hydrogens, 1 sulfur, 4 oxygens

Products:

    > 1 carbon, 4 hydrogens, 1 sulfur, 2 oxygens

As you can see, there is a differing amount of hydrogens and oxygens on both sides. The balanced equation looks like this:

1 CO₂ + 4 H₂S + 1 O₂ ---> 1 CH₂O + 4 S + 3 H₂O

Below is the amount of each element on each side of the reaction.

Reactants:

    > 1 carbon, 8 hydrogens, 4 sulfurs, 4 oxygens

Products:

    > 1 carbon, 8 hydrogens, 4 sulfurs, 4 oxygens

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An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia with excess carbon dioxide. Determin
dolphi86 [110]

Answer:

The theoretical yield of urea = <u>120.35kg</u>

The percent yield for the reaction = <u>72.70%</u>

Explanation:

Lets calculate -

The given reaction is -

2NH_3(aq)+CO_2 →CH_4N_2O(aq)+H_2O (l)

Molar mass of urea CH_4N_2O= 60g/mole

Moles of NH_3 = \frac{62.8kg/mole}{17g/mole} (since Moles=\frac{mass  of  substance}{mass of one mole})

                     = 4011.76 moles

Moles of CO_2 = \frac{105kg}{44g/mole}

                = \frac{105000g}{44g/mole}

                = 2386.36 moles

Theoritically , moles of NH_3 required = double the moles of CO_2

    but , 4011.76 , the limiting reagent is NH_3

Theoritical moles of urea obtained = \frac{1 mole CH_4N_2O}{2mole NH_3}\times4011.76 mole NH_3

                                                      = 2005.88mole CH_4N_2O

Mass of 2005.88 mole of CH_4N_2O =2005.88 mole \times\frac{60g CH_4N_2O}{1mole CH_4N_2O}

                                                     = 120352.8g

                                                     120352.8g\times \frac{1kg}{1000g}

                                                     = 120.35kg

Therefore , theroritical yeild of urea = 120.35kg

Now , Percent yeild = \frac{87.5kg}{120.35kg}\times100

                                 72.70%

Thus , the percent yeild for the reaction is 72.70%

8 0
3 years ago
Match each item to its proper disposal method. Answers to be used more than once.
salantis [7]

Answer:

1. a)

2. a)

3. b)

4. d)

Explanation:

The disposal method is how we throw away the wastes. In a chemical lab, the correct disposal method guarantees the security of the environment and the humans and animals that may be in contact with the materials.

So:

1. Excess chemical: Because it can be toxic, it may be disposed of in the appropriate waste container, which will depend on the characteristics of the material;

2. Reaction mixture: As the excess chemical, it can be toxic, so it must be disposed of at an appropriate waste container;

3. Used filter paper: Generally, the solids in the filter paper is not toxic, so it can be thrown away in the trash can;

4. Cracked or chipped beaker: Because the beaker is made of glass, it can cut when broken, so it must go to a broken glass box, that will protect the people that will deal with it.

8 0
3 years ago
Describe what happens to mass before and after a change in matter
Gala2k [10]
a. The mass is greater before the change occurs.
3 0
3 years ago
If an atom should form from its constituent particles,
tia_tia [17]

Answer:

(b) matter is lost and energy is released

Explanation:

When atoms are being formed from its constituent components it weighs less this is called mass defect so the answer would be (b) matter is lost and energy is released.

8 0
3 years ago
What is meant by conversion of energy
MissTica

the process of changing one form of energy into another

4 0
3 years ago
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