Answer:
The heat lost by the water 
3.8 KJ
The heat gain by ice 
= 228.76 J
The heat required to melt the ice 
= 3340 J
Explanation:
Mass of ice cube 
= 10 gm
Initial temperature of ice cube 
= 0 °c
Mass of water 
= 100 gm
Initial temperature of water 
= 20 °c
Final temperature of mixture 
= 10.93 °c
(a). Total heat lost by the water 
( - )
⇒ 100 × 4.184 (20 - 10.93)
⇒ 3.8 KJ
This is the heat lost by the water.
(b). Heat gained by the ice cube = 
⇒ = 10 × 2.093 × ( 10.93 - 0)
⇒ = 228.76 J
This is the heat gain by ice.
(C). Heat required to melt the ice = × Latent Heat
⇒ = 10 × 334
⇒ = 3340 J
This is the heat required to melt the ice.
Answer:
Difussion
Explanation:
Diffusion is the result of a totally random phenomenon in which the molecules of a fluid come and go between two vessels that can be connected by a pipe. These molecules travel in a single direction, where the solute is more concentrated to where it is more diluted.
This movement of particles will be modified according to the length or area of the pipe and the concentration of solute. The greater the difference in solute concentration along the tube, the greater the diffusion
Because if an electron was in an atom, it would allow two atoms to combine without exploding and disentigrating, therfore there would be no suck thing as nuclear fission (nuclear bomb)
A. surface tension
I hope this helps
Since there is no sample, let us assume 100 g of the solution:
(22.2% of 100 g) / (46.0254 g HCOOH/mol) = 0.48234 mol HCOOH
(100 g - 22.2 g) = 77.8 g = 0.0778 kg water
(0.48234 mol HCOOH) / (0.0778 kg) = 6.1997 mol/kg = 6.20 m HCOOH
(77.8 g H2O) / (18.01532 g H2O/mol) = 4.3185 mol H2O
(0.48234 mol HCOOH) / (0.48234 mol + 4.3185 mol) = 0.100 [the mole fraction of HCOOH]
