Answer:
The value of smaller resistor is 248 Ω.
Explanation:
Voltage divider circuit is used to convert a higher voltage to a smaller voltage with the help of resistors which are connected in parallel.
As shown in the circuit, Vs is the source voltage, R₁ and R₂ are the two resistors and V₀ is the output voltage.
Applying KVL in the circuit, the output voltage is given by :
According to the problem, R₂ = 310Ω , V₀ = 5 V and Vs = 9 V. Substitute these values in the above equation.
R₁ = 248Ω
The resistance of the circuit will definitely increase. This can be proved by the Ohm's Law where it is said that the potential difference across a conductor is directly proportional to the current and the proportionality constant is known as the resistance. The law is expressed as V = IR. As we can see, when the voltage remains constant while the current decreases then the resistance will increase.<span />
Answer:
3.71 eV
Explanation:
λ = Wavelength of light = 224 nm = 224 x 10⁻⁹ m
c = speed of electromagnetic wave = 3 x 10⁸ m/s
V₀ = stopping potential = 1.84 volts
W₀ = Work function of the metal = ?
Using the equation
= 5.94 x 10⁻¹⁹
= 3.71 eV
It is B. false that an instrument used to detect a static electric charge is called an ammeter. It is actually called an electroscope. Ammeter measures current.
