The area of the plates must have is(A)= 9.91×10⁷ m²
<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>
To calculate the the value of a area of the plates of a capacitor, we are using the formula,
C=
Or, A= 
Here we are given,
C= The desired capacitance of a capacitor.
= 0.23F
d=distance of separation between the plates.
=3.8mm= 0.0038m.
= permittivity of the vacuum.
=8.854×10⁻¹²F/m
We have to calculate the area of the plates must have = A m².
Now we put the known values in the above equation, we can get
A=
Or, A=
Or, A= 9.91×10⁷ m²
From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²
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Answer:
There are 75 people in the class. The number of boys is 48 and the number of girls is 27. The percentage of girls is 36% of 75.
Explanation:
Answer:
The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.
Explanation:
Brightness of the bulb is given as
since all bulbs are connected in parallel so here voltage across each bulb will remain same and resistance of each bulb is "R"
So here power across each bulb will remain the same always.
So there will be no effect on the power or brightness of bulb.
Now we also know that equivalent resistance is given as
so here equivalent resistance will decrease on adding more resistance in parallel.
so correct answer will be
The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.
-- Since the sphere is a conductor, the charge on it will move around
until it's evenly distributed on the surface of the sphere. When every
tiny smitch of charge is the same distance from the charge around it,
they won't need to move around any more.
-- At that point, the situation at the center of the sphere will be:
For every smitch of charge on the surface, causing en electric field
at the center, there is another smitch, of the same size and in exactly
the opposite direction, canceling out the field of the first one.
Every smitch of charge on the surface causes a tiny bit of electric field
at the center, and they all cancel each other.
It turn out that if the sphere is hollow, then the electric field at EVERY
point inside it is zero, not only at the center.
It's exactly the same idea as a sphere with uniform, homogeneous mass.
For that sphere, the gravity at the center is zero.
