Answer:
V_{average} = , V_{average} = 2 V
Explanation:
he average or effective voltage of a wave is the value of the wave in a period
V_average = ∫ V dt
in this case the given volage is a square wave that can be described by the function
V (t) =
to substitute in the equation let us separate the into two pairs
V_average =
V_average =
V_{average} =
we evaluate V₀ = 4 V
V_{average} = 4 / 2)
V_{average} = 2 V