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stealth61 [152]
2 years ago
9

a 77 N net force is applied to a box which slides horizontally across a floor for 6.7 m. What amount of work is done on the box

by the net force ?
Physics
1 answer:
ArbitrLikvidat [17]2 years ago
7 0
W=fd
W=77*6.7
W=515.9 J
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A block with a mass of 2kg is pushed 20cm and a constant speed up an incline that makes a 40 degree angle with the floor. how mu
Alexxx [7]

work done will be 2.5872 J

Given :

mass of block = 2kg

distance travelled by block = 20cm

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To Find :

Work done by gravity

Solution :

Gravity is defined as the force that attracts a body towards the earth or towards any other physical body having mass.

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8 0
2 years ago
A rocket car on a horizontal rail has an initial mass of 2500 kg and an additional fuel mass of 1000 kg. At time t0 the rocket m
slamgirl [31]

Answer: Acceleration of the car at time = 10 sec is 108 m/s^{2} and velocity of the car at time t = 10 sec is 918.34 m/s.

Explanation:

The expression used will be as follows.

M\frac{dv}{dt} = u\frac{dM}{dt}

\int_{t_{o}}^{t_{f}} \frac{dv}{dt} dt = u\int_{t_{o}}^{t_{f}} \frac{1}{M} \frac{dM}{dt} dt

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           = (3500 - 95t_{f})s

v_{f} = -2900 ln(\frac{3500 - 95 t_{f}}{3500}) m/s

Also, we know that

     a = \frac{dv_{f}}{dt_{f}} = \frac{u}{M} \frac{dM}{dt}

        = \frac{u}{3500 - 95 t} \times (-95) m/s^{2}

        = \frac{95 \times 2900}{3500 - 95t} m/s^{2}

At t = 10 sec,

v_{f} = 918.34 m/s

and,   a = 108 m/s^{2}

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