Answer:
d= 0.242 mm
Explanation:
Slit width (d ) = ?
Screen distance ( D ) = 1.25 m
Wave length of light λ = 600 nm
Distance of n the dark fringe from centre
= n λ D / d
Here n = 2
so
d= 0.242 mm
a 77 N net force is applied to a box which slides horizontally across a floor for 6.7 m. What amount of work is done on the box
1 answer:
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Answer:
The minimum thickness = 83.92 nm
Explanation:
The relation between the wavelength in a particular medium and refractive index
where ;
= wavelength of the light in vacuum
n = refractive index of medium with respect to vacuum
For one phase change :
Replacing 1.43 for n and 480 nm for λ; we have:
t = 83.92 nm
Thus; the minimum thickness = 83.92 nm