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stealth61 [152]

3 years ago

9

a 77 N net force is applied to a box which slides horizontally across a floor for 6.7 m. What amount of work is done on the box

by the net force ?

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

W=fd
W=77*6.7
W=515.9 J

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Ohm’s Law<br>pls answer this photos

Rudiy27

Answer:

Trial 1: 2 Volts, 0 %

Trial 2: 2.8 Volts, 0%

Trial 3: 4 Volts, 0 %

Explanation:

Th experimental values are given in the table, while the theoretical value can be found by using Ohm/s Law:

V = IR

<u>TRIAL 1</u>:

V = IR

V = (0.1 A)(20 Ω)

<u>V = 2 volts</u>

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(2 - 2)/2| x 100%

<u>% Difference = 0 %</u>

<u>TRIAL 2</u>:

V = IR

V = (0.14 A)(20 Ω)

<u>V = 2.8 volts</u>

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(2.8 - 2.8)/2.8| x 100%

<u>% Difference = 0 %</u>

<u></u>

<u>TRIAL 3</u>:

V = IR

V = (0.2 A)(20 Ω)

<u>V = 4 volts</u>

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(4 - 4)/4| x 100%

<u>% Difference = 0 %</u>

7 0

4 years ago

Two skaters skate toward each other, each moving at 3.3 m/s. Their lines of motion are separated by a perpendicular distance of

vredina [299]

Answer:

4.4 rad/s

Explanation:

When the 2 skaters is spinning with a distance of 1.5m, their rotation radius is half of that distance, which is 1.5/2 = 0.75m.

Then their moments of inertia, given that their mass being 51 kg, is (treating them as point mass particle):

$I = Mr^2 = 2Mr^2 = 51*0.75^2 = 38.25 kg.m^2$

When they change from linear motion to rotational motion, their energy must be conserved:

$E_L = E_r$

$2*(0.5Mv^2) = 2*(0.5I\omega^2)$

$\omega^2 = \frac{Mv^2}{I}$

$\omega = v\sqrt{\frac{M}{I}}$

$\omega = 3.3\sqrt{\frac{51}{38.25}} = 4.4 rad/s$

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3 years ago

Which statement best describes the variables in a controlled experiment?

podryga [215]

control is constant for given set of readings.

set indep var

observe dep var

6 0

3 years ago

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Hey v sauce here massive ti ts here there is many black wholes in space there is one in my A&& as well

exis [7]

I’m confused but I will answer that small snippet of a question, and it is that nobody knows how many black holes are in space but scientist have estimated that there are 10 million to a billion black holes

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3 years ago

A 2.75 kg block is pulled across a flat, frictionless floor with a 5.11 N force directed 53.8° above horizontal. What is the tot

Softa [21]

Answer:

F = 3.01 N

Explanation:

Given that,

Mass of a block, m = 2.75 kg

Force applied to the block, F = 5.11 N

It is directed 53.8° above horizontal.

We need to find the total force acting on the block. The force acting on it is given by :

$F=F\cos\theta\\\\F=5.11\times \cos53.8\\F=3.01\ N$

So, 3.01 N of force is acting on the block.

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3 years ago