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stealth61 [152]

2 years ago

9

a 77 N net force is applied to a box which slides horizontally across a floor for 6.7 m. What amount of work is done on the box

by the net force ?

1 answer:

ArbitrLikvidat [17]2 years ago

7 0

W=fd
W=77*6.7
W=515.9 J

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What is the speed of sound in air with temperature of 355.8 k

nikklg [1K]

Answer:

Explanation:

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nirvana33 [79]

It gets larger because
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3 years ago

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Natali [406]

Answer:

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2 years ago

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spin [16.1K]

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2 years ago

A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is

harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

Where,

$d_g =$ Depth of glass

$n_w =$ Refraction index of water

$n_g =$ Refraction index of glass

$n_{air} =$ Refraction index of air

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I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

$d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})$

$d'w = 4.041cm$

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0

3 years ago