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3 years ago

What happens when two forces act in the same direction?

1 answer:

4 0

If 2 forces act on a object in the same direction, the net force is equal to the sum of 2 forces. This always results in a stronger force than either individual forces alone

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What are the 4 elements of amazonite

steposvetlana [31]

Aluminum, silicon, potassium and oxygen.

6 0

3 years ago

Helium is most likely to behave as an ideal gas when its under what?

rodikova [14]

Answer:

Low pressure and high temperature :)

Have an amazing day!!

Please rate and mark brainiest!!

7 0

2 years ago

U test a substance using red litmus paper turns blue based on these results is the substance acidic or base

Blizzard [7]

Answer:

basic in nature

Explanation:

Litmus Test -

It is the very basic test , used to determine if the solution is acidic in nature or is basic in nature .

There are two type of litmus paper available , i.e. , blue and red .

If the solution is acidic in nature ,

putting a blue litmus paper turns red ,

and putting a red litmus paper would not show any change .

And , hence it can be concluded that the solution is acidic in nature .

Similarly ,

If the solution is basic in nature ,

putting a red litmus paper turn blue ,

and putting a blue litmus paper would not show any change .

And , hence it can be concluded that the solution is basic in nature .

6 0

4 years ago

A flask contains 0.83molof neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the

blsea [12.9K]

Answer:

V = 56.72 L

Explanation:

Given data:

Number of mole of neon gas = 0.83 mol

Temperature = 35°C

Pressure = 0.37 atm

Volume of gas = ?

Solution;

Temperature = 35°C (35+273 =308K)

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

Now we will put the values in formula.

V = nRT/P

V = 0.83 mol ×0.0821 atm.L/mol.K ×308K / 0.37 atm

V = 20.99 L/ 0.37

V = 56.72 L

6 0

4 years ago

Find percent yield:

saveliy_v [14]

Answer: The percent yield of the reaction is 91.8 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $B_5H_9$ :

Given mass of $B_5H_9$ = 4.0 g

Molar mass of $B_5H_9$ = 63.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of }B_5H_9=\frac{4g}{63.12g/mol}=0.0634mol$

For oxygen gas:

Given mass of oxygen gas = 10.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{10g}{32g/mol}=0.3125mol$

The chemical equation for the reaction of $B_5H_9$ and oxygen gas follows:

$2B_5H_9+12O_2\rightarrow 5B_2O_3+9H_2O$

By Stoichiometry of the reaction:

12 moles of oxygen gas reacts with 2 moles of $B_2H_5$

So, 0.3125 moles of oxygen gas will react with = $\frac{2}{12}\times 0.3125=0.052mol$ of $B_2H_5$

As, given amount of $B_2H_5$ is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

12 moles of oxygen gas produces 5 moles of $B_2O_3$

So, 0.3125 moles of oxygen gas will produce = $\frac{5}{12}\times 0.3125=0.130moles$ of water

Now, calculating the mass of $B_2O_3$ from equation 1, we get:

Molar mass of $B_2O_3$ = 69.93 g/mol

Moles of $B_2O_3$ = 0.130 moles

Putting values in equation 1, we get:

$0.130mol=\frac{\text{Mass of }B_2O_3}{69.63g/mol}\\\\\text{Mass of }B_2O_3=(0.130mol\times 69.63g/mol)=9.052g$

To calculate the percentage yield of $B_2O_3$ , we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of $B_2O_3$ = 8.32 g

Theoretical yield of $B_2O_3$ = 9.052 g

Putting values in above equation, we get:

$\%\text{ yield of }B_2O_3=\frac{8.32g}{9.052g}\times 100\\\\\% \text{yield of }B_2O_3=91.8\%$

Hence, the percent yield of the reaction is 91.8 %

6 0

4 years ago