Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
I hope you enjoyed my explanation. :)
Answer:
y² + 8y + 16
Step-by-step explanation:
Given
(y + 4)²
= (y + 4)(y + 4)
Each term in the second parenthesis is multiplied by each term in the first parenthesis, that is
y(y + 4) + 4(y + 4) ← distribute both parenthesis
= y² + 4y + 4y + 16 ← collect like terms
= y² + 8y + 16
Answer:
Step-by-step explanation:
We have the exponential function of the form:
And it goes through the points (0, 13) and (3, 832).
Hence, when we substitute in 0 for x, we should get 13 for y. Therefore:
Since anything to the zeroth power is 1, this yields:
So, we determined that the value of a is 13.
So, our function is now:
We will need to determine b. We know that y equals 832 when x is 3. Hence:
Divide both sides by 13:
Take the cube root of both sides:
Hence, our b value is 4.
Therefore, our entire equation is:
Well, we know perimeter is just adding all the lengths together.
And we already know 2 of the lengths, so we know the rest. 11 1/2 is the same as the opposite side, and 6 1/3 is the same as the opposite side.
So the sides are 6 1/3, 6 1/3, 11 1/2, 11 1/2.
Add them up:
6 1/3 + 6 1/3 + 11 1/2 + 11 1/2.
Improper fractions:
19/3 + 19/3 + 23/2 + 23/2.
Common denominator, (6):
38/6 + 38/6 + 69/6 + 69/6 = 214/6.
Simplify:
214/6 = 35 2/3
Answer:
4 feet of wall should be on each side of the painting.
Step-by-step explanation:
Given that a 4 foot wide painting should be centered on a 12 foot wide wall, to determine how many feet (X) should be on each side of the painting, the following equation must be solved:
(Total wide of the wall - wide of the painting) / 2 = X
(12 - 4) / 2 = X
8/2 = X
4 = X
Therefore, 4 feet of wall should be on each side of the painting.
