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densk [106]
2 years ago
14

Q1. The equation for the reaction between sulfur dioxide and oxygen is shown.

Chemistry
1 answer:
Delicious77 [7]2 years ago
3 0

The mole fraction of sulfur trioxide in the equilibrium mixture is 0.353.
Hence option (B) is the correct answer.

<h3>What is mole fraction ?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

We have to use algebra here,

Because in the equation O_2 has a stoichometry of 1, the other have 2,

let O_2 = x

You started with 2 moles, so the moles of O_2 at equilibrium will be 2 - X

SO_3 has a stoichiometry of 2 compared to O_2, so will be 2X

( not minus from anything as you started with no moles of SO_3)

And then SO_2  will also be 2X as it’s stoichiometry is 2, but as you started with 2 moles it will be 2-2X

If you add these in an equation to get total moles it’s

2 - 2X  +  2 - X + 2X = 3.4 (total given)

and then gathering together becomes 4-X = 3.4

so,

4 = 3.4 + X

so,

x = 0.6

Therefore,

the moles of SO_3  = 2 x 0.6 = 1.2

mole fraction = moles of the gas / total moles of gas

mole fraction = 1.2 / 3.4 = 0.353

Learn more about mole fraction here ;

brainly.com/question/25994904

#SPJ1

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3 0
3 years ago
Select the most likely product for this reaction:
Rama09 [41]

Answer:

A

Explanation:

just took it on EDG 2020

6 0
3 years ago
Read 2 more answers
An experiment requires that enough C3H8O be used to yield of oxygen .
blsea [12.9K]

Answer: So if you had 570 cm of ribbon, then 570%2F8.5=67.05 which means that about 67 students can do the experiment (round down to the nearest whole number).

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8 0
3 years ago
N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol
docker41 [41]

Answer:

A

Explanation:

Recall that Δ<em>H</em> is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:


\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)

Therefore, from the chemical equation, we have that:


\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} +  \Delta H^\circ_f \text{ H$_2$O}  \right]   -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}

In conclusion, our answer is A.

5 0
2 years ago
A gas has a volume of 3L at 200 kPa. What will its volume be if the pressure is changed to 500 kPa?
marta [7]

Answer:

6L

Explanation:

<em>if it's 3L per 200kPa</em>

then it would be;

4L per 300kPa

5L per 400kPa

6L per 500kPa

that's how i'd work it out in my head, hope it helps, but not sure though!

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3 years ago
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