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1 year ago

Q1. The equation for the reaction between sulfur dioxide and oxygen is shown.

1 answer:

3 0

The mole fraction of sulfur trioxide in the equilibrium mixture is 0.353.
Hence option (B) is the correct answer.

<h3>What is mole fraction ?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

We have to use algebra here,

Because in the equation $O_2$ has a stoichometry of 1, the other have 2,

let $O_2$ = x

You started with 2 moles, so the moles of $O_2$ at equilibrium will be 2 - X

$SO_3$ has a stoichiometry of 2 compared to $O_2$ , so will be 2X

( not minus from anything as you started with no moles of $SO_3$ )

And then $SO_2$ will also be 2X as it’s stoichiometry is 2, but as you started with 2 moles it will be 2-2X

If you add these in an equation to get total moles it’s

2 - 2X + 2 - X + 2X = 3.4 (total given)

and then gathering together becomes 4-X = 3.4

so,

4 = 3.4 + X

so,

x = 0.6

Therefore,

the moles of $SO_3$ = 2 x 0.6 = 1.2

mole fraction = moles of the gas / total moles of gas

mole fraction = 1.2 / 3.4 = 0.353

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A certain liquid X has a normal boiling point of 111.20 celsius and a boiling point elevation constant Kb=0.95. calculate the bo

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Answer: the boiling point is = 137.325°C

Explanation:

From the formula: ∆Tb= Kb*m

From the question, Kb= 0.95, m= 27.5, T1= 111.2°C

Substitute into ∆Tb= Kb*m

∆Tb= 0.95*27.5= 26.125

∆Tb= T2-T1

Hence

T2- 111.2=26.125

T2= 26.125+ 111.2= 137.325°C

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2 years ago

What would be the minimum energy Emin required to excite a hydrogen atom from its lowest energy level

Wewaii [24]

The minimum energy required to excite a hydrogen atom from its lowest energy level is 10.2 eV.

<h3>What is excitation?</h3>

The term excitation has to do with the promotion of an electron from a lower to a higher energy level.

In this case, we are dealing with the hydrogen atom having only one electron. Thus, the minimum energy required to excite a hydrogen atom from its lowest energy level is 10.2 eV.

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1 year ago

A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:

bekas [8.4K]

Answer: The standard enthalpy of formation of $H_2O(g)$ is -252.1 kJ/mol.

Explanation:

The balanced chemical reaction is,

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactantss}]$

Putting the values we get :

$\Delta H=[2\times H_f{Fe}+3\times H_f{H_2O}]-[1\times H_f{Fe_2O_3}+3\times H_f{H_2}]$

$67.9kJ=[(2\times 0)+(3\times H_f{H_2O})]-[(1\times -824.2kJ/mol)+3\times 0kJ/mol)]$

$H_f{H_2O}=-252.1kJ/mol$

Thus standard enthalpy of formation of $H_2O(g)$ is -252.1 kJ/mol.

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2 years ago

What is the typical percentage (by mass of elements other than hydrogen and helium in stars that are forming right now in the vi

Ipatiy [6.2K]

Considering mass percentages, stars in the vicinity of the sun contain only 2% other elements by mass. Other than the main components, hydrogen and helium, stars have some heavier elements such as carbon, nitrogen, oxygen and iron. These elements are found near or in the star's core and are ejected into space when the star dies.

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3 years ago

A student has 100. mL of 0.400 M CuSO4(aq) and is asked to make 100. mL of 0.150 M CuSO4(aq) for a spectrophotometry experiment.

ValentinkaMS [17]

Answer:

<u></u>

<u>a. 37.5 mL</u>

<u></u>

<u>b. See the description below</u>

Explanation:

<u><em>a. Volume of 0.400 M CuSO₄(aq) required for the preparation</em></u>

In dissolutions, since the number of moles of solute is constant, the equation is:

$C_1\times V_1=C_2\times V_2$

Substitute and solve for V₁

$0.400M\times V_1=0.150M\times 100ml$

$V_1=0.150M\times 100.ml/0.400M=37.5ml$

<u><em>b. Briefly describe the essential steps to most accurately prepare the 0.150 M CuSO₄(aq) from the 0.400 M CuSO₄(aq)</em></u>

You will use the stock solution, the funnel, the buret, and distilled water.

i) Using the funnel, fill in the buret with with 50 ml of the stock solution, i.e. the 100. ml of 0.400 M CuSO₄(aq) solution.

ii) Pour 37.5 ml of the stock solution from the burete into the volumetric flask.

iii) Carefully add disitlled water to the 37.5ml of the stock solution in the volumetric flask until the mark (50 ml) on the volumetric flask.

iv) Put the stopper and rotate the volumetric flask to homegenize the solution.

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3 years ago