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densk [106]
2 years ago
14

Q1. The equation for the reaction between sulfur dioxide and oxygen is shown.

Chemistry
1 answer:
Delicious77 [7]2 years ago
3 0

The mole fraction of sulfur trioxide in the equilibrium mixture is 0.353.
Hence option (B) is the correct answer.

<h3>What is mole fraction ?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

We have to use algebra here,

Because in the equation O_2 has a stoichometry of 1, the other have 2,

let O_2 = x

You started with 2 moles, so the moles of O_2 at equilibrium will be 2 - X

SO_3 has a stoichiometry of 2 compared to O_2, so will be 2X

( not minus from anything as you started with no moles of SO_3)

And then SO_2  will also be 2X as it’s stoichiometry is 2, but as you started with 2 moles it will be 2-2X

If you add these in an equation to get total moles it’s

2 - 2X  +  2 - X + 2X = 3.4 (total given)

and then gathering together becomes 4-X = 3.4

so,

4 = 3.4 + X

so,

x = 0.6

Therefore,

the moles of SO_3  = 2 x 0.6 = 1.2

mole fraction = moles of the gas / total moles of gas

mole fraction = 1.2 / 3.4 = 0.353

Learn more about mole fraction here ;

brainly.com/question/25994904

#SPJ1

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Which of these formulas is NOT consistent with the guidelines for creating ionic compounds? Mark all that apply.
iVinArrow [24]

Answer:

d

Explanation:

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8 0
3 years ago
Which atoms make up a molecule of sodium bicarbonate.
Ratling [72]

Answer:

Its chemical formula is NaHCO3. Its formula consists of one sodium (Na) atom, one hydrogen (H) atom, one carbon (C) atom and three oxygen (O) atoms.

Explanation:

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8 0
2 years ago
What is one major purpose for an animal to produce unusual sounds, display bright
bezimeni [28]
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7 0
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7 0
3 years ago
You are given 25.00 mL of an acetic acid solution of unknown concentration. You find it requires 35.75 mL of a 0.2750 M NaOH sol
oksano4ka [1.4K]

Answer:

a. 0.393M CH₃COOH.

b. 2.360% of acetic acid in the solution

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺

<em>That means 1 mole of acid reacts per mole of NaOH.</em>

Moles of NaOH to reach the equivalence point are:

35.75mL = 0.03575L × (0.2750mol / L) = <em>9.831x10⁻³ moles of NaOH</em>

As 1 mole of acid reacts per mole of NaOH, moles of CH₃COOH in the acid solution are 9.831x10⁻³ moles.

a. As the volume of the acetic acid solution is 25.00mL = 0.02500L, the molarity of the solution is:

9.831x10⁻³ moles / 0.02500L =

<h3>0.393M CH₃COOH</h3>

b. Molar mass of acetic acid is 60g/mol. The mass of 9.831x10⁻³ moles is:

9.831x10⁻³ moles ₓ (60g / mol) = <em>0.590g of CH₃COOH</em>.

As volume of the solution is 25.00mL, the percentage of acetic acid is:

(0.590g CH₃COOH / 25.00mL) ₓ 100 =

<h3>2.360% of acetic acid in the solution</h3>

8 0
3 years ago
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