Answer:
A. 2.4 x 10¹⁴ J
Explanation:
m (mass) = 2.7 x 10⁻³ kg
c = 3.0 x 10⁸ m/s
Plug these numbers into the equation E=mc²
E=mc²
E= (2.7 x 10⁻³)(3.0 x 10⁸)²
E= 2.43 x 10¹⁴
So, the answer is A. 2.4 x 10¹⁴ J.
The mass of that would be formed will be 18.22 grams
<h3>Stoichiometric calculations</h3>
Let us first look at the balanced equation of the reaction:
The mole ratio of Y to is 2:3.
Mole of 10.0 grams of Y = 10/88.9 = 0.11 moles
Mole of 10.0 grams = 10/71 = 0.14 moles
3/2 of 0.11 = 0.165. Thus, is limiting in availability.
Mole ratio of and = 3:2
Equivalent mole of = 2/3 x 0.14 = 0.093 moles.
Mass of 0.093 moles =0.093 x 195.26 = 18.22 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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I believe it’s 164.0878 grams
Answer:
The answer should be, B, The periodic table
Answer:
Magnesium, Mgstart text, M, g, end text, is a group 2 element that will form 2+ cations. Because it usually forms cations of only one type, we don't need to specify its charge. We can simply refer to the cation in the ionic compound as magnesium. ... Therefore, the name for the compound is magnesium phosphide.
Explanation:
(this may or not be correct)
-also i finished that drawing you wanted :p-