As per energy conservation we know that
Energy enter into the bulb = Light energy + Thermal energy
so now we have
energy enter into the bulb = 100 J
Light energy = 5 J
now from above equation we have
A 10 kg object experiences an acceleration of 2 m/s squared. What net force was applied to the object?
1 answer:
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Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) =
⇒ P =
⇒ P = 16
This is the pressure inside the cylinder.
Let force applied on the brake pad =
Area of the brake pad ()= 1.7
Thus the pressure on the brake pad () =
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P =
⇒ 16 =
⇒ = 16 ×
Put the value of we get
⇒ = 16 × 1.7
⇒ = 27.2 lb
This the total force applied during braking.
The force applied on one wheel = =
= 6.8 lb
⇒ The force applied on one wheel during braking.