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svlad2 [7]
3 years ago
15

A 10 kg object experiences an acceleration of 2 m/s squared. What net force was applied to the object?

Physics
1 answer:
Nastasia [14]3 years ago
4 0

F = ma

= 10kg × 2m/s

= 20N

Answer : 20N

Explanation :

F = Force (N)

m = mass (kg)

a = acceleration (m/s)

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car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of a. The car
Luba_88 [7]

Answer:

0.572

Explanation:

First examine the force of friction at the slipping point where Ff = µsFN = µsmg.

the mass of the car is unknown,

The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.

First the tangential direction

∑Ft =Fft =mat

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Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2

So going backwards and plugging in Ffc =m2atπr/ 2r =πmat

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3 years ago
Which of the following is equivalent to 140 centiliters?
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Which bulbs would be on and or off if :
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Europa, a satellite of Jupiter, is believed to have a liquid ocean of water (with a possibility of life) beneath its icy surface
Goryan [66]

Answer:

so maximum velocity for walk on the surface of europa is  0.950999 m/s

Explanation:

Given data

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mass = 4.8×10^22 kg

to find out

maximum velocity for walk on the surface of europa

solution

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now

we put all value in equation 1

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