Answer:
distance between the charges is 5.12 × 10⁶ m
Explanation:
charges q₁ = -130.0 C
q₂ = 180 C
force between the charges = 8 N
force between two charge
value of K =8.975 × 10⁹ N.m²/C²
r = 5.12 × 10⁶ m
hence, distance between the charges is 5.12 × 10⁶ m.
Answer:
Explanation:
opposite charges attract
same charges repel
neutral charges don't attract or repel
Answer:
<h2>After 3.06seconds</h2>
Explanation:
Given that the following data are
acceleration a= 3,2m/s^2
distance s=15m,
time t=?
Applying the formula for the equation of motion we have
s=ut+1/2at^2
we no initial velocity (u=0)
substituting our given values into the expression we have
15=0*t+1/2(3.2)t^2
15=1/2(3.2)t^2
15=3.2t^2/2
30=3.2t^2
t^2=30/3.2
t^2=9.375
Squaring both sides we have
t=√9.375
t=3.06seconds
<em>It will take the sled 3.06 seconds to get to the bottom</em>
Answer:
It will take both pumps 3.08 hours to fill the tank working together.
Explanation:
Pump A can fill the tank in 5 hours. Assuming that the pump gives out a steady flow of water, in one hour, pump A can fill 1/5th of the tank. Similarly, pump B in an hour, fills up 1/8th of the tank.
We must add up these two values, in order to find how much of the tank the two pumps can fill up together in one hour.
1/5 +1/8 =13/40
So 13/40 of the tank is filled in an hour. We need to find how many hours it will take for the entire tank to be filled. To do so, divide 40 by 13. This gives:
3.08 hours to fill up the tank.
Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²