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ANTONII [103]
3 years ago
9

A 60-Hz 3-phase induction motor is required to drive a load at approximately 850 rpm. How many poles should the motor have

Engineering
1 answer:
Anastaziya [24]3 years ago
7 0

Answer:

8 poles

Explanation:

Given

Frequency, f = 60Hz

Speed, n_s = 850rpm

Required

Calculate the number of poles the motor should have?

To solve this question, we make use of synchronous angular velocity  formula

n_s = \frac{120f}{P}

Where

P = Number\ of\ Poles

Substitute values for n_s and f in n_s = \frac{120f}{P}

850 = \frac{120 * 60}{P}

850 = \frac{7200}{P}

Multiply both sides by P

P * 850 = \frac{7200}{P} * P

P * 850 = 7200

Divide both sides by 850

\frac{P * 850}{850} = \frac{7200}{850}

P = \frac{7200}{850}

P = 8.47058823529

However, the number of poles must be an integer.

So:

P = 8

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A 50 mm 45 mm 20 mm cell phone charger has a surface temperature of Ts 33 C when plugged into an electrical wall outlet but not
romanna [79]

Answer:

C = $0.0032 per day

Explanation:

We are given;

Dimension of cell phone; 50 mm × 45 mm × 20 mm

Temperature of charger; T1 = 33°C = 306K

Emissivity; ε = 0.92

convection heat transfer coefficient; h = 4.5 W/m².K

Room air temperature; T∞ = 22°C = 295K

Wall temperature; T2 = 20°C = 293 K

Cost of electricity; C = $0.18/kW.h

Chargers are usually in the form of a cuboid, and thus, surface Area is;

A = (50 × 45) + 2(50 × 20) + 2(45 × 20)

A = 6050 mm²

A = 6.05 × 10^(-3) m²

Formula for total heat transfer rate is;

E_t = hA(T1 - T∞) + εσA((T1)⁴ - (T2)⁴)

Where σ is Stefan Boltzmann constant with a value of; σ = 5.67 × 10^(-8) W/m².K⁴

Thus;

E_t = 4.5 × 6.05 × 10^(-3) (306 - 295) + (0.92 × 6.05 × 10^(-3) × 5.67 × 10^(-8)(306^(4) - 293^(4)))

E_t = 0.7406 W = 0.7406 × 10^(-3) KW

Now, we know C = $0.18/kW.h

Thus daily cost which has 24 hours gives;

C = 0.18 × 0.7406 × 10^(-3) × 24

C = $0.0032 per day

6 0
3 years ago
Show that -40 F is approximately equal to -40 C.
V125BC [204]

Answer: Please see below the explanation.

Explanation:

The Celsius (ºC) and Farenheit (ºF), are different temperature scales, but both have identifiable values for two important physical phenomena, water freezing point and water boiling point.

For º C, these are follows:

Freezing Point= 0º C            Boiling Point: 100ºC

For º F, we have the following:

Freezing Point= 32º F            Boiling Point: 212 ºF

Assuming that all steps (in each scale) between two following values are equal, we have 100 º C between both points in ºC, and 190º in ºF, so degrees in Farenheit are "shorter" than in Celsius, being the relationship, approximately the following:

1 º C = 9/5 ºF.

Taking into account that, by definition, 0ºC = 32º F, we can use the following equations in order to convert ºC to ºF, and viceversa:

ºC = (ºF-32) 5/9    

ºF = 32 + 9/5ºC

Now, let's calculate -40ºF, in ºC:

ºC= (-40-32)* 5/9 = -40º C

Let's do the same, converting -40ºC to ºF:

ºF = 32 + (-40)*9/5 = 32 + (-72) = -40ºF.

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3 years ago
Calculate the scale and speed of the pattern in order to gain useful results for a turbine operate at 150 rev/min at height diff
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Answer:

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3 years ago
I am sending an email to my teacher. Is this mature enough?
nirvana33 [79]
I dislike how you wrote the 0’s. But honestly Teachers don’t really care as long as they can read it. So sure send it I guess
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3 years ago
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