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GREYUIT [131]
3 years ago
6

The relationship between the pressure drop per unit length along a smooth-walled, horizontal microfluidic channel and the variab

les that affect the pressure drop can be expressed by:________
Engineering
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

Δp = ∫( D, p, u, V)

Explanation:

The pressure drop formula is given above. It determines the relation between pressure drop per unit along with smooth walled channel. The formula is from Buckingham pi theorem in which repeating and non repeating variables are used together.

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Explanation:

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2 years ago
Match the following items with their correct description.
Lera25 [3.4K]

Answer:

A. Manufacturers rating capacity ↔  3. Must be marked on all jacks; must not be exceeded

B. Block Used to lift and hold heavy loads, allow them for travel ↔ 1. Place the jack head against this

C. Level surface ↔ 4. Place this under the base of the jack when it's necessary to provide a firm foundation

D. Jack ↔ 2. Used to lift and hold heavy loads, allow them for travel

Explanation:

The manufacturers rating for a jack is labelled on all jacks and should be referenced to compare with the load to be lifted so as to ensure a safe and successful lifting.

In order to lift a load, such as a car, it is required to place the jack on a level surface to provide balance during the lifting task

The head of the jack is placed against the block for lifting heavy objects for proper performance

8 0
4 years ago
Refrigerant-134a enters a 28-cm-diameter pipe steadily at 200 kPa and 20°C with a velocity of 5 m/s. The refrigerant gains heat
Alexandra [31]

Answer:

V = 0.30787 m³/s

m = 2.6963 kg/s

v2 =  0.3705 m³/s

v2 = 6.017 m/s

Explanation:

given data

diameter = 28 cm

steadily =200 kPa

temperature = 20°C

velocity = 5 m/s

solution

we know mass flow rate is

m = ρ A v

floe rate V = Av

m = ρ V

flow rate = V = \frac{m}{\rho}

V = Av = \frac{\pi}{4} * d^2 * v1

V = \frac{\pi}{4} * 0.28^2 * 5

V = 0.30787 m³/s

and

mass flow rate of the refrigerant is

m = ρ A v

m = ρ V

m = \frac{V}{v} = \frac{0.30787}{0.11418}

m = 2.6963 kg/s

and

velocity and volume flow rate at exit

velocity = mass × v

v2 = 2.6963 × 0.13741 = 0.3705 m³/s

and

v2 = A2×v2

v2 = \frac{v2}{A2}

v2 = \frac{0.3705}{\frac{\pi}{4} * 0.28^2}

v2 = 6.017 m/s

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Great app idea generation is not a gift given to a selected few, instead, it is a process by which any of us are able to carefully explore step by step methods to find our own solution to any problem. Whether you are a seasoned creator or a novice, we have provided a few recommendations to challenge and aid you as you create your next masterpiece.

if I am right then make me brainliest

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3 years ago
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