The volume of 0.175 M Na3PO4 solution that is necessary to completely react withn 95.4 ml of 0.102 M cuCl2 is
<u>calculation</u>
<u> </u><em> Step 1: </em> write the equation for reaction
3CuCl2 (aq) + 2Na3Po4 → Cu3(PO4)2 + 6 NaCl
Step 2 : find the moles of CuCl2
moles = molarity x volume in liters
volume in liters = 95.4 /1000 =0.0954 L
moles is therefore = 0.0954 L x 0.102 M= 0.00973 moles
Step : use the mole ratio to calculate the moles of Na3Po4
The mole ratio of CuCl2 : Na3PO4 is 3:2 therefore = 0.00973 x2/3= 0.00649 moles
Step 4 : find the volume of Na3PO4
volume = moles/molarity
= 0.00649 mole / 0.175=0.037 M
It would use rapid combustion
