Answer:
see below
Step-by-step explanation:
If we let X represent the number of bagels produced, and Y the number of croissants, then we want ...
(a) Max Profit = 20X +30Y
(b) Subject to ...
6X +3Y ≤ 6600 . . . . . . available flour
X + Y ≤ 1400 . . . . . . . . available yeast
2X +4Y ≤ 4800 . . . . . . available sugar
_____
Production of 400 bagels and 1000 croissants will produce a maximum profit of $380.
__
In the attached graph, we have shaded the areas that are NOT part of the solution set. (X and Y less than 0 are also not part of the solution set, but are left unshaded.) This approach can sometimes make the solution space easier to understand, since it is white.
The vertex of the solution space that moves the profit function farthest from the origin is the one we are seeking. The point that does that is (X, Y) = (400, 1000).
Answer:
<h2>
301.593</h2><h2 />
Step-by-step explanation:
surface area = 2πrh + 2πr²
where r = 4 km radius
h = 8 km
<u>plugin values into the formula</u>
surface area = 2πrh + 2πr²
= 2π (4) 8 + 2π (4)²
= 201.062 + 100.531
= 301.593 km²
Let
x: number of regular basketball
y: number of long-distance basket
We have the following system of equations:
2x + 3y = 96
x + y = 45
Solving the system we have
y = 45-x
2x + 3 (45-x) = 96
2x +135 -3x = 96
-x = 96 -135
x = 39
Then,
y = 45-x
y = 45-39
y = 6
answer
were made
regular baskets = 39
long-distance baskets = 6
Answer:
$4,881.56
Step-by-step explanation:
The future value formula is ...
FV = P(1 +r/n)^(nt)
where principal P is invested at annual rate r compounded n times per year for t years.
You have P=3300, n=12, r=0.028, t=14, so the future value is ...
FV = $3300(1 +0.028/12)^(12·14) = $4881.56
There would be $4881.56 in the account after 14 years.