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lorasvet [3.4K]
3 years ago
11

How does a convex mirror form an image?

Physics
2 answers:
MariettaO [177]3 years ago
5 0

The convex mirror form an image by bouncing the light away from a focal point.

Answer: Option D

<u>Explanation: </u>

A diverging mirror is a reflecting surface which is a spherical one. The bulging side of the convex mirror will face towards the light source. It is a diverging mirror in which rays diverge upon after reflection. These are often used in the mirrors that are in the automobiles.  

The image that is formed by the convex mirror cannot be displayed on the screen. Hence, they are called as Virtual image. The resulting image by the convex mirror is upright, virtual and size diminished.  

inna [77]3 years ago
3 0

Answer:

D

Explanation:

Just took the test

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A solid piece of clear transparent material has an index of refraction of 1.61. If you place it into a clear transparent solutio
NISA [10]

Answer:

1.61

Explanation:

According to Oxford dictionary, refractive index is, ''the ratio of the velocity of light in a vacuum to its velocity in a specified medium.''

If the clear transparent solid disappears when dipped into the liquid, it means that the index of refraction of the solid and liquid are equal.

Hence, when a transparent solid is immersed in a liquid having the same refractive index, there is no refraction at the boundary between the two media. As long as there is no refraction between the two media, the solid can not be seen because the solid and liquid will appear to the eye as one material.

7 0
3 years ago
If you hold a horizontal metal bar several centimeters above the ground and move it through grass, each leaf of grass bends out
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<span>If you spin fast enough, the impact of the glad will break the blade of grass before it can move out of the way. In the same way that if you kick an empty can, it will move out of the way, but if you shoot it with a gun, the bullet will cut through the can before it can move. Keep in mind a mower blade turns at probably 10,000 RPMs.</span>
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3 years ago
What is the freezing point of an aqueous solution that boils at 101 degrees C? Kfp = 1.86 K/m and Kbp = 0.512 K/m. Enter your an
astra-53 [7]

Answer:

-3.63 degree Celsius

Explanation:

We are given that

Boiling point of solution=T_b=101^{\circ} C

Boiling point water=100 degree Celsius

K_f=1.86K/m

K_b=0.512 K/m

\Delta T_b=T-T_0

Where T=Boiling point of solution

T_0=Boiling point of pure solvent

\Delta T_b=101-100=1^{\circ}C

\Delta T_b=k_bm

Using the formula

1=0.512\times m

Molality,m=\frac{1}{0.512} m

\Delta T_f=k_fm

Using the formula

\Delta T_f=\frac{1}{0.512}\times 1.86

\Delta T_f=3.63 C

We know that

\Delta T_f=T_0-T_1

Where T_0 =Freezing point of solvent

T_1= Freezing point of solution

Using the formula

3.63=0-T_1

Freezing point of water=0 degree Celsius

T_1=0-3.63=-3.63 C

Hence, the freezing point of solution=-3.63 degree Celsius

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3 years ago
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Answer:

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Explanation:

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Answer:

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