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MatroZZZ [7]
3 years ago
7

A greyhound's velocity changes from 10 meters per second to 15 meters per second in 0.5 second. What is the greyhound's average

acceleration?
Physics
2 answers:
forsale [732]3 years ago
6 0
The correct answer is 5 m/s^2
alexgriva [62]3 years ago
4 0
I think it is 5 m/s  
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In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, s
Nonamiya [84]

Answer:

(a) 1.11 m

(b) 4760 kgm/s  

Explanation:

height of plane (h) = 370 m

velocity (v) = 56 m/s

mass (m) = 85 kg

force = 1.2 x 10^{5} N = 120,000 N

(a) We can get the minimum depth of snow from the equation below

   force x depth = kinetic energy on impact

 f x d = 0.5 x m x v^{2}

 120000 x d = 0.5 x 85 x 56^{2}

 d= (0.5 x 85 x 56^{2}) ÷ 120000 = 1.11 m

(b) the magnitude of impulse is equal to the momentum of the paratrooper and his gear

 = m x v

= 85 x 56 = 4760 kgm/s  

7 0
3 years ago
PLS ANSWER WITH EXPLANATION OR SOLUTION (WILL GIVE 50 PTS)
Fed [463]

Answer:

\underline{ \boxed{F_m =  3.35 { \times 10}^{ - 2} N}}

Explanation:

since \: in \: this \: case \to \: \underline{ v }\: is \perp \: to \:\underline{ q} \\ then \: the \: magnetic \: force \: (F_m) \: is \:  max = qvB \sin(90)  \\ F_m = qvB  \times (1) = qvB \\ hence \to \\ F_m = qvB  \\ where \\  \: q = 0.75 C : v = 235m {s}^{ - 1}  : B = 1.9 { \times 10}^{ - 4} T  \\ therefore \to \\ F_m = 0.75 \times 235 \times 1.9 { \times 10}^{ - 4} \\ F_m = 176.25 \times 1.9 { \times 10}^{ - 4} \\ F_m = 0.0334875  = 3.35 { \times 10}^{ - 2} N \\ \boxed{F_m =  3.35 { \times 10}^{ - 2} N}

3 0
2 years ago
The energy carried by sound waves is called -
goldenfox [79]

Answer:

kinetic mechanical energy

8 0
2 years ago
Read 2 more answers
Please helo me to 1st question<br>​
k0ka [10]

Explanation:

6 min in seconds:

6×60

<h2><u>360</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u><u> </u></h2><h2 /><h2 />

6 min in hours:

<h2><u>0</u><u>.</u><u>1</u><u> </u><u>hours</u></h2>
6 0
3 years ago
The earth has radius R. A satellite of mass 100 kg is in orbit at an altitude of 3R above the earth's surface. What is the satel
Vera_Pavlovna [14]

Answer:

W= 61.3 N

Explanation:

The only force acting on the satellite is the one due to the attraction from Earth, which obeys the Newton's Universal Law of Gravitation, as follows:

Fg =G*ms*me / (res)²

This force, also obeys the Newton's 2nd Law, so we can write the following equation:

G*ms*me*/ (res)² = ms* a = ms*g

We call to the product of the mass times the acceleration caused by gravity (g), the weight of this mass, so we can write as follows:

G*ms*me / (res)² = ms*g = W (1)

where G = 6.67*10⁻11 N*m²/kg², ms= 100 kg, me= 5.97*10²⁴ kg, and

res=  4 *re = 4*6.37*10⁶ m.

Replacing all these known values in (1), we get the value of W:

W =(( 6.67*5.97/(4*6.37)²) *( 10⁻¹¹ * 10²⁴ /10¹²) )* 100 N = 61.3 N

6 0
3 years ago
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