A greyhound's velocity changes from 10 meters per second to 15 meters per second in 0.5 second. What is the greyhound's average
2 answers:
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Answer:
2.24 m/s²
Explanation:
Using equation of motion
s = ut + at²
u = 0 , t = 3.17 s , s = 11.26 m
Put these values in the equation above
11.26 = 0 +.5 x a( 3.17)²
a = 2.24 ms⁻².
So acceleration due to gravity on that planet will be 2.24 m s⁻².
Answer:
A) v = 1,675 10³ m / s , B) r₂ = 11,673 10⁶ m
Explanation:
A) This exercise we must use Newton's second law, where the forces of gravity are the Moon
F = m a
acceleration is centripetal
a = v² / r
force is the force of universal attraction
F = G m M / r²
we substitute
G m M / r² = m v² / r
v² = G M / r
distance
r = R_moon + h
r = 1.74 10⁶ +1.0786 10⁴
r = 1,750786 10⁶ m
we calculate
v = √ (6.67 10⁻¹¹ 7.36 10²² / 1.75 10⁶)
v = √ (2,8052 10⁶)
v = 1,675 10³ m / s
B) let's use energy conservation
Starting point. In the mountain
Em₀ = K + U = ½ m v² + G m M / r
Final point. Where the speed is zero
= U = G mM / r₂
Em₀ = Em_{f}
½ m v² + G m M / r = G mM / r₂
1 / r₂ = (½ v₂ + G M / r) / GM
let's calculate
1 / r₂ = (½ (1,675 10³)² + 6.67 10⁻¹¹ 7.36 10²² / 1.75 10⁶) /(6.67 10⁻¹¹ 7.36 10²²)
1 / r₂ = (1,4028 10⁶ + 2,805 10⁶) / 49.12 10¹¹
1 / r₂ = 8.5664 10⁻⁷
r₂ = 11,673 10⁶ m
Actually Welcome to the Concept of the Ohms Law,
According to the Ohms law,
V = I*R, where, V = Voltage, I = Current, R = resistance,
so here given as, V = 240 V, I = 32 A,
so we get as, R = 240/32
R = 7.5 ohms,
===> The resistant R is ==> 7.5 ohms.