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nalin [4]
2 years ago
13

Calculate the mass, in grams, of 1.2000 mol Mg₃N₂

Chemistry
1 answer:
fredd [130]2 years ago
7 0
So what do you want me to do
Explanation
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Question 1
Salsk061 [2.6K]

Answer:

Part A:

"360 grams of NaCl can be dissolved in 1 L water. So, 2000 grams sugar can be dissolved in 1 L water then we can say that the solubility of salt is lesser in water as to sugar and both heightened by increasing the temperature. If we make a batch of 800 L we can add sugar, 1600 kg at 25 0c. We can add salt is 288 kg at 25 0c and the ingredient tomato is having low solubility."

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/8061-describe-the-sequence-of-adding-ingredients-to-make-the-recipe.html

Part B:

'Manufacturers can generate new value minimize cost and increase operational stability by focusing on 4 broad areas; Management, Supply Circle, Product Design, and Value Recovery.'

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/2807911-what-changes-could-be-made-to-optimize-the-manufacturing-process.html

4 0
2 years ago
Use the iupac nomenclature rules to give the name for this compound - n2o3.
wel
  By  use   IUPAC  nomenclature   rule  compound  N2O3  is  named  as  

Dinitrogen  trioxide  (  answer  d)

Nitrogen (N2) is  named  before  oxygen(O3)  since    they  are  arranged  alphabetically.  In   addition  the  prefix  Di  is   used   infront  of  nitrogen  since    they  are  two  nitrogen  atoms   while  prefix  tri  is   used  infront  of  oxide  since  they  are 3   oxygen   atoms
8 0
2 years ago
Read 2 more answers
Which types of orbitals are found in the principal energy level n = 2?
AfilCa [17]
Remember this:

1) n is principal quantum number and represents the energy level.

2) l is the second quantum number and represent the type of orbital.

3) l can take values from 0 to n - 1

4) each number of l is associated with a type of orbital.  This table shows the equivalence:
 
l number       type of orbital

0                    s

1                    p

2                    d

3                     f

With that, you can tell that n = 2 permits l = 0 and 1, which is orbitals s and p.

Therefore, the answer is the option D) s, p.
3 0
3 years ago
Read 2 more answers
What are The usages of transducer in ultrasonic??
Gennadij [26K]

Answer:they are used to generate sound waves in the ultrasonic range

Explanation:transducers are used to generate sound waves in the ultrasonic range ,by turning electrical energy into sound

8 0
3 years ago
Osmium metal, the densest element, has a density of 22.6 g/mL, while hydrogen, the least dense element, has a density of 8.99 e-
KengaRu [80]

Answer:

1. Volume of osmium = 0.044 mL

2. Volume of Hydrogen = 11123.47 mL

3. Osmium is 251390 times denser than hydrogen

Explanation:

From the question given above, the following data were obtained:

Density of osmium = 22.6 g/mL

Density of Hydrogen = 8.99×10¯⁵ g/mL

Mass of osmium = 1 g

Mass of Hydrogen = 1 g

1. Determination of the Volume of osmium.

Density of osmium = 22.6 g/mL

Mass of osmium = 1 g

Volume of osmium =?

Density = mass /volume

22.6 = 1 / volume

Cross multiply

22.6 × volume = 1

Divide both side by 22.6

Volume = 1 / 22.6

Volume of osmium = 0.044 mL

2. Determination of the Volume of Hydrogen.

Density of osmium = 8.99×10¯⁵ g/mL

Mass of osmium = 1 g

Volume of osmium =?

Density = mass /volume

8.99×10¯⁵ = 1 / volume

Cross multiply

8.99×10¯⁵ × volume = 1

Divide both side by 8.99×10¯⁵

Volume = 1 / 8.99×10¯⁵

Volume of Hydrogen = 11123.47 mL

3. Determination of the number of times osmium is denser than hydrogen.

Density of osmium (Dₒ) = 22.6 g/mL

Density of Hydrogen (Dₕ) = 8.99×10¯⁵ g/mL

Dₒ / Dₕ = 22.6 / 8.99×10¯⁵

Dₒ / Dₕ = 251390

Cross multiply

Dₒ = 251390 × Dₕ

Thus, osmium is 251390 times denser than hydrogen.

5 0
2 years ago
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