Answer:
All of the above statements are true.
Explanation:
All matter is composed of atoms of which have subatomic particles. Subatomic particles are electrons, protons and neutrons. Each particle has electric charges.
Electrons have a negative charge, protons have a positive charge and neutrons have zero charge.
Between two nearby charges initially at rest, a type of forces, called electrostatic, is always established in such a way that, if the charged particles are small enough so that they can be considered punctual, the following conditions are met:
-
The force established between the two has a direction that coincides with an imaginary straight line that joins the two charges.
- The force exerted on one load points towards the other when the two have different signs, one positive and the other negative. (attractive force).
- The sense of force is directed to the opposite side of the charge when both have the same sign (repulsive force).
Answer:
2960 N
Explanation:
Convert rev/min to rad/s:
150 rev/min × (2π rad/rev) × (1 min / 60 s) = 50π rad/s
Sum of forces in the centripetal direction:
∑F = ma
T = m v² / r
T = m ω² r
T = (0.2 kg) (50π rad/s)² (0.6 m)
T = 2960 N
Answer:
The size of the labor force is 19300.
Explanation:
Given that,
Adult population = 30000
Number of employed = 17700
Number of unemployed = 1600
Suppose, The labor force is comprised of those who are working for any number of hours (the employed) and those who are out of work but actively looking for a job the unemployed)
We need to calculate the size of the labor force
The labor force is comprised of number of employed person and number of unemployed person.
That means,
Labor Force = Employed + Unemployed
Hence, The size of the labor force is 19300.
Answer:
As follows,
Explanation:
KE=1/2mv^2
In 1st question,
KE=1/2mv^2=1/2*0.05*12=0.3 J [50g=0.05 kg]
In 2nd question,
KE=1/2mv^2
6.8=1/2*0.046*v^2
v=sqrt(6.8/0.023)
v=17.19
In 3rd question,
KE=1/2mv^2
63/392=m
m=0.16kg=160g
For 4th,
a.
1st case,
KE=1/2mv^2=1/2*28*2.4^2=80.64
2nd case,
KE=1/2mv^2=1/2*28*3.7^2=191.66
Change in KE=191.66-80.64=11.02
b.Speed/velocity gained
Answer:
0.765m
Explanation:
gravitational potential energy GPE = mass * acceleration due to gravity * height
Given
GPE = 30Joules
Mass m = 4kg
acceleration = 9.8m/s²
Required
Height h
From the formula
h = GPE/mg
h = 30/4(9.8)
h = 30/39.2
h = 0.765m\
Hence the height of the counter is 0.765m
