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Yuki888 [10]
3 years ago
5

Will mark as Brainliest.

Chemistry
2 answers:
Serga [27]3 years ago
5 0
The amount of kinetic energy required for the molecules to break free of the intermolecular forced in the liquid is raised because the other ones don’t make sense
Katen [24]3 years ago
3 0

Answer:

he never got his brainliest...

Explanation:

You might be interested in
Without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the follo
siniylev [52]

Answer:

∆H > 0

∆Srxn <0

∆G >0

∆Suniverse <0

Explanation:

We are informed that the reaction is endothermic. An endothermic reaction is one in which energy is absorbed hence ∆H is positive at all temperatures.

Similarly, absorption of energy leads to a decrease in entropy of the reaction system. Hence the change in entropy of the reaction ∆Sreaction is negative at all temperatures.

The change in free energy for the reaction is positive at all temperatures since ∆S reaction is negative then from ∆G= ∆H - T∆S, we see that given the positive value of ∆H, ∆G must always return a positive value at all temperatures.

Since entropy of the surrounding= - ∆H/T, given that ∆H is positive, ∆S surrounding will be negative at all temperatures. This is so because an endothermic reaction causes the surrounding to cool down.

3 0
2 years ago
Please answer for me thanks...
tatuchka [14]

Explanation:

Since mole ratio of O2 : NH3 = 7 : 4,

Volume of NH3 = 50dm³ * 4/7 = 28.57dm³.

5 0
3 years ago
If you have 1.00 mole of F2 at 1.00 atm of pressure and 0°C, what is the volume of F2?
ss7ja [257]

Answer:

V=22.4L

Explanation:

Hello,

In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm}  \\\\V=22.4L

Best regards.

4 0
2 years ago
A sample of sandstone consists of only silica (SiO2) and calcite (CaCO3). When sandstone is heated, calcium carbonate decomposes
anzhelika [568]

Answer:

0

Explanation:

To calculate, the mass of Carbondioxide is 3.45mg

Then the decomposition of Carbondioxide gives 0 on calculation

5 0
3 years ago
Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1
Arte-miy333 [17]

Answer:

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰   =  -  RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰   =   - 1.987 x 273 x  ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

8 0
3 years ago
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