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Yuki888 [10]
3 years ago
5

Will mark as Brainliest.

Chemistry
2 answers:
Serga [27]3 years ago
5 0
The amount of kinetic energy required for the molecules to break free of the intermolecular forced in the liquid is raised because the other ones don’t make sense
Katen [24]3 years ago
3 0

Answer:

he never got his brainliest...

Explanation:

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What is an element made up of?<br>​
Dvinal [7]

Answer:

An element is a pure substance and is made of only one type of atom; it cannot be broken down into a simpler substance. Overview: In this activity, students practice using the periodic table to look up chemical symbols of elements and use paper circles to construct and compare models of elements and compounds.

Explanation:

please mark me brainliest.please!

6 0
3 years ago
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Romashka [77]

Answer:1

Explanation:cause castle told me

4 0
3 years ago
Compare the charges and masses of<br> protons, neutrons, and electrons.
lapo4ka [179]

Answer:

Protons, neutrons, and electrons: Both protons and neutrons have a mass of 1 amu and are found in the nucleus. However, protons have a charge of +1, and neutrons are uncharged. Electrons have a mass of approximately 0 amu, orbit the nucleus, and have a charge of -1.

Explanation:

4 0
3 years ago
A compound has the formula C8H8 and does not contain any double or triple bonds. All the carbon atoms are chemically identical a
Ann [662]

Answer:

<h3>There's no way for C8H8 to exist without double bonds. To fulfill the rule of the octet, four bonds must be formed by each carbon. This can only be done in C8H8 through the formation of double bonds.</h3>

Explanation:

7 0
4 years ago
Calculate the concentration (M) of sodium ions in a solution made by diluting 50.0 mL of a 0.874 M solution of sodium sulfide to
statuscvo [17]

Answer:

Since one mole Na₂S ionised to give 2moles Na⁺ ion, hence concentration of sodium ion in the solution is (2 × 0.1748)M = 0.3496 M

≈0.350 M

Explanation:

From the question it is clear that,  

Initial volume of sodium sulphide solution is (v₁) = 50mL

Initial concentration of sodium sulphide solution is (s₁) =0.874 M

Final volume of sodium sulphide solution is (v₂) = 250mL

Let, the final concentration of sodium sulphide solution is s₂, then according to acidimetry-alkalimetry,

v₁ × s₁ = v₂ × s₂

Or, s₂ = v₁ × s₁/v₂

= 50 × 0.874 / 250

= 0.1748 M

Therefore, concentration of 250mL sodium sulphide solution is 0.1748 M

Since one mole Na₂S ionised to give 2moles Na⁺ ion, hence concentration of sodium ion in the solution is (2 × 0.1748)M = 0.3496 M

≈0.350 M

5 0
3 years ago
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