Question

If a jet's cruising altitude is 32,200 ft (to three significant figures), this distance in km is: (1 mile = 1.61 km; 1 mile = 5280 ft)

Answer 1

If a jet's cruising altitude is 32,200 ft (to three significant figures), this distance in km is 9.82 km.

What are significant figures?

Significant figures are the number of digits in a value, often a measurement, that contributes to the degree of accuracy of the value. We start counting significant figures at the first non-zero digit.

In this case, given the conversion factors from miles to kilometres and from miles to feet, we can directly compute the jet’s cruising altitude in kilometres as shown below:

$32200 ft X \frac{1 mile}{5280 ft} X \frac{1.61km}{1 mile}$

=9.82 km

Learn more about the significant figures here:

brainly.com/question/14359464

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