Answer:
2
Step-by-step explanation:
Step 1. <em>Find a coterminal angle that falls be 0 and 2π.
</em>
Remember that cscθ is a periodic function. It repeats every 2π radians.
If n is an integer, cscθ = csc(θ ± 2πn)
csc(17π/6) = csc(12π/6 + 5π/6)
= csc(2π + 5π/6)
= csc(5π/6)
Step 2. <em>Use the unit circle to evaluate cscθ.
</em>
cscθ = 1/sinθ
Let θ = 5π/6
In a unit circle (below), the sine of an angle is y.
sinθ = ½
cscθ = 1/sinθ
= 1/(½)
= 2
Calculating could be confusing and leading to an incorrect answer.
The student should have phrased it to be "the difference between the product of 5 and y and 15", as the way the student writes it implies that 5y is being subtracted from 15 instead of the other way around.
A. The perimeter of quadrilaterals are same when x=2.
B. The area of quadrilaterals are same when x=4.6
<u>Step-by-step explanation</u>:
A. <u>Perimeter of the quadrilaterals must be equal.</u>
- Perimeter of square is 4a.
- where, a = 6
- Perimeter of rectangle is 2(l+b).
- where, l = 2 and b = (3x+4)
Perimeter of square = Perimeter of rectangle
4(6) = 2(2+3x+4)
⇒ 24 = 2(3x+6)
⇒ 24 = 6x + 12
⇒ 6x = 12
⇒ x = 12/6
x = 2
For x=2, the perimeters of both the quadrilaterals are same.
B. <u>Area of the quadrilaterals must be equal.</u>
- Area of square is a².
- where, a = 6.
- Area of rectangle is l
b. - where, l = 2 and b = (3x+4)
Area of square = Area of rectangle
(6)² = 2(3x+4)
36 = 6x+8
6x = 28
x = 28/6
x = 4.6
For x=4.6, the area of both the quadrilaterals are same.