When the u-235 nucleus is struck with a neutron, the zn-72 and sm-160 nuclei are produced, along with some neutrons. How many ne
1 answer:
4 neutrons that are produced along with the Zn and sm. The complete final equation is: ²³⁵U + ¹n → + 4 n
Atomic mass, the quantity of matter contained in an atom of an element.
1) In the left side of the transmutation equation appears:
²³⁵U + ¹n →
Deleting the atomic number (subscript to the left) because the question does not show them as it is focused on a number of neutrons.
2) The right side of the transmutation equation has:
→ +?
3) The total mass number of the left side is 235 + 1 = 236
4) The total mass number of Zn and sm on the right side is 160 + 72 = 232
5) Then, you are lacking 236 - 232 = 4 unit masses on the right side which are the 4 neutrons that are produced along with the Zn and sm.
The complete final equation is:
²³⁵U + ¹n → + 4 n
Learn more about the atomic mass here:
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Answer:
<u>One lone-Pair is present in Ammonia</u>
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Explanation:
The number of valence electron in N = 5
The number of Valence electron in H = 1
The formula of ammonia = NH3
Total valence electron in ammonia molecule = 5 +3(1) = 5+3 = 8
The lewis structure suggest that :
Nitrogen completes its octet by sharing the electron pair with 3 hydrogen atoms.
3 electron of Nitrogen are involved in sharing with Hydrogen
So,<u><em> remaining two electron are left non-bonded</em></u> . Hence they exist as lone- pair
So, there is only 1 lone pair in the ammonia molecule .
The shape of NH3 is bent according to VSEPR theory . This is so because the presence of 1 lone pair causes more repulsion and occupy more space.
Thus the lone pair is changing the shape of the ammonia molecule . It also increase the dipole moment of the molecule , which gives polarity to it.
