1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aliya0001 [1]
2 years ago
6

Which compound can act as both a Brønsted-Lowry acid and a Brønsted-Lowry base?

Chemistry
2 answers:
allsm [11]2 years ago
7 0
Water. 
In certain circumstances, water acts as a proton donor.
e.g NH3(aq) + H2O(l) --> NH4+(aq) + OH-(aq)

In other circumstances, water can act as a proton acceptor.
e.g HNO3(aq) + H2O(l) --> H3O+(aq) + NO3-(aq)
denis23 [38]2 years ago
5 0

Answer:

A: water

Explanation:

You might be interested in
Is the equation above balanced or unbalanced? Explain? Worth 55 points.
Paul [167]

Answer:

For me, it is balanced

Explanation:

Because the amount of element Zn reaction is equal the production. Also as the amount of Hydrogen and Chloride in the reaction and the production are equal.

8 0
3 years ago
Read 2 more answers
When you walk, you push against the floor, and _________.
Taya2010 [7]
When you walk, you push against the floor, and t<span>he floor pushes back against you.

Answer: B. The floor pushes back agaisnt you. 

Good luck with your studies, I hope this helps~!
</span>
7 0
2 years ago
Balance the combustion eqation; __C5H + __O2 ---&gt; __CO2+__H2O
stira [4]
This equation C5H + O2 ---> CO2 + H2O has a mistake.

C5H is wrong. You missed the subscript of H.

I will do it for you assuming some subscript to show you the procedure, but you have to use the right equation to get the right balanced equation.

Assuming the tha combustion equation is C5H12 + O2 ---> CO2 + H2O

First you need to  balance C, so you put a 5 before CO2 and get

C5H12 + O2 ---> 5CO2 + H2O

Now you count the hydrogens: 12 on the left and 2 on the right. So put a 6 before H2O and get:

C5H12 + O2 ---> 5CO2 + 6H2O

Now count the oxygens: 2 on the left and 16 on the right, so put an 8 on before O2:

=> C5H12 + 8O2 ---> 5CO2 + 6H2O.

You can verify that the equation is balanced
8 0
2 years ago
What components did you collect to convert your two molecules of pyruvate to acetyl-coa?
GenaCL600 [577]
<span>You need to have NAD+ as a source of oxidation for the pyruvate, as well as a supply of coenzyme A. CO2 is released by the pyruvate as a carboxyl group is removed</span>
5 0
2 years ago
The equilibrium constant for the chemical equation is Kp = 5.23 at 191 °C. Calculate the value of the Kc for the reaction at 191
Lapatulllka [165]
To convert from Kp to Kc, you need this formula---> Kp= Kc (RT)^Δn, where Δn= gas moles of product- gas moles of reactants. since you did not give a reaction formula, I can't calculate Δn. but all once you find it out. just plug it. 

Kp= Kc (RT)^Δn------------------> Kc= Kp/[(RT)^Δn]
 Kp= 5.23
R= 0.0821
T= 191 C= 464 K
Δn= ?

Kc= 5.23/ (0.0821 x 464)^Δn= ???

7 0
3 years ago
Other questions:
  • A 7.70 L 7.70 L container holds a mixture of two gases at 47 ° C. 47 °C. The partial pressures of gas A and gas B, respectively,
    14·1 answer
  • Something that has mass and volume; its made up of atoms
    10·1 answer
  • A family is another name for a group on the<br> table of elements.
    13·2 answers
  • Which of the following statements is TRUE? Question 1 options: There is a "heat tax" for every energy transaction. A spontaneous
    15·1 answer
  • Complete the following sentence: "During a chemical reaction."
    11·1 answer
  • Can anyone please help?
    10·1 answer
  • There’s bots who create questions and then suddenly get a response and there’s me who waits hours for a response. Lol really nic
    13·1 answer
  • How does the valence bond theory describe a covalent bond formation?
    5·1 answer
  • Please help me with these questions please...
    15·1 answer
  • What is the empirical formula for a compound if a sample contains 1.0 g of S and 1.5 g of O?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!