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2 years ago

Which compound can act as both a Brønsted-Lowry acid and a Brønsted-Lowry base?

2 answers:

7 0

Water.
In certain circumstances, water acts as a proton donor.
e.g NH3(aq) + H2O(l) --> NH4+(aq) + OH-(aq)

In other circumstances, water can act as a proton acceptor.
e.g HNO3(aq) + H2O(l) --> H3O+(aq) + NO3-(aq)

denis23 [38]2 years ago

5 0

Answer:

A: water

Explanation:

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Which compound is classified as a hydrocarbon? A) butanal B) butyne C) 2-butanol D) 2-butanone

fenix001 [56]

Answer:

butyne

Explanation:

alkane, alkene, and alkyne are all examples of hydrocarbons.

butyne = alkyne

7 0

3 years ago

3.0 cm x 4.0 cm x 1.0 cm [?]cm^3

CaHeK987 [17]

Explanation:

Hi there!!

you asked to multiply these all right,

you can simply multiply it ,

=3cm × 4 cm × 1cm

= 12cm^2×1cm (4×3=12)

= 12cm^3 (12×1=12)

Therefore, theanswer is 12 cm^3.

Hope it helps..

4 0

3 years ago

If 550 mL of a 3.50 M KCl solution are set aside and allowed to evaporate until the volume of the solution is 275 mL, what will

tatiyna

Answer:

Explanation:

Molarity = number of moles / volume

If 550 mL of a 3.50 M KCl solution are set aside and allowed to evaporate until the volume of the solution is 275 mL, which is half of 550 mL, the molarity of the solution with the same number of moles of KCl is 3.5 * 2 = 7.00 M

8 0

1 year ago

Read 2 more answers

What type of energy is caused by positive and negative charges in matter

levacccp [35]

Answer:

Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged.

Explanation:

7 0

2 years ago

Read 2 more answers

What is the standard emf of a galvanic cell made of a cd electrode in a 1.0 m cd(no3)2 solution and a cr electrode in a 1.0 m cr

Natali5045456 [20]

Standard reduction potential of Cd2+ = -0.403 v
Standard reduction potential of Cr3+ = -0.74 v

Here, reduction potential of Cd2+ is higher as compared to Cr3+. Hence, it will preferentially undergo reduction.

The electrochemical cell is represented as
Cr/Cr3+// Cd2+/Cd

Now, standard EMF of cell = E = ECd2+/Cd - ECr3+/Cr
= - 0.403. - (-0.74)
= 0.337 v

8 0

3 years ago