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lisabon 2012 [21]
3 years ago
10

Given the reaction:

Chemistry
1 answer:
dezoksy [38]3 years ago
3 0

Answer:

V = 22.34 L

Explanation:

Given data:

Volume of O₂ needed = ?

Temperature and pressure = standard

Number of molecules of water produced = 6.0× 10²³

Solution:

Chemical equation:

2H₂ + O₂       →      2H₂O

Number of moles of water:

1 mole contain 6.022× 10²³ molecules

6.0× 10²³ molecules ×  1 mole  /  6.022× 10²³ molecules

0.99 mole

Now we will compare the moles of oxygen and water.

                  H₂O         :            O₂  

                    2            :              1

               0.996         :          0.996

Volume of oxygen needed:

PV = nRT

V = nRT/P

V = 0.996 mol × 0.0821 atm.L/mol.K ×  273.15 K / 1 atm

V = 22.34 L

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8 0
3 years ago
. Which substance is the limiting reactant when 2 g of S reacts with 3 g of O2 and 4 g of NaOH according to the following chemic
Ksivusya [100]

Answer:

S is the limiting reagent.

Explanation:

To find the limiting reactant we must first write the balanced chemical reaction. It must be correctly balanced so that we can find the proper mole ratios.

2 S (s) + 3 O2 (g) + 4 NaOH (aq) → 2 Na2SO4 (aq) + 2 H2O (l)

After this we will convert our measurements to moles. For mass we do this by dividing by the molar mass.

2g ÷ 32.06 = 0.06238mol S

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0.06238mol S × 2/2 = 0.06238mol H2O

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3 0
3 years ago
!!please help asap ty!!
Bess [88]

Answer:

2.89× 10²³ atom

Explanation:

Given data:

Number of atoms of Zn = ?

Number of moles of Zn = 0.48 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atom

0.48 mol ×  6.022 × 10²³ atom / 1mol

2.89× 10²³ atom

7 0
3 years ago
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luda_lava [24]
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3 years ago
What's the sequence of a single complete engine cycle?
erastovalidia [21]

Answer:

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5 0
3 years ago
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