The possible number and location of all subatomic are one of them is electrically neutral, while the other has a stable electronic configuration.
<h3>What are subatomic particles?</h3>
Subatomic particles are those particles that are present inside the atoms. They are electron, neutron, and proton. They are charged particles, protons are positively charged, electrons are negatively charged and neutrons are neutral.
The protons and electrons totally contribute to the atomic mass of the elements.
Thus, the subatomic particles are electrically neutral and stable to electronic configurations.
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Answer:
true
Explanation:
PV=nRT
The ideal gas law states that PV = NkT, where P is the absolute pressure of a gas, V is the volume it occupies, N is the number of atoms and molecules in the gas, and T is its absolute temperature. The constant R is called the Boltzmann constant
Just look at the number in front also called coefficient (you have to balance the equations first, but all the questions here are balanced, so no worries). for q1.
in the balanced equation, the number in front of aluminum oxide is 2 (2 - this number Al2O3) and for aluminium is 4 as in (4 Al). so the ratio is 2:4. simplified it is 1:2. or write it out fully
2 Al2O3: 4 Al
ignore everything after the number.
2:4
same as 1:2
Aluminium oxide to oxygen
2 Al2O3: 3 O2
2:3
aluminum to oxygen
4 Al: 3 O2
4:3
question 2
Mercury oxide to Mercury
2 HgO : 2 Hg
2:2
same as 1:1
Mercury oxide to oxygen
2 HgO : O2
since oxygen in this case does not have a number written in front of it, the default is 1.
2: 1.
you should be able to do the rest
The new temperature of the piece of lead will be 37.5°C
SPECIFIC HEAT CAPACITY:
- The amount of heat absorbed or released by a substance can be calculated by using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or released (J)
m = mass of substance (g)
c = specific heat capacity
∆T = change in temperature (°C)
According to this question,
Q = 1.90J
m = 1.29g
T1 = 26°C
T2 = ?
c = 0.128 J/g°C
1.90 = 1.29 × 0.128 × (T2- 26°C)
1.90 = 0.165 (T2 - 26°C)
1.90 = 0.165T2 - 4.29
1.90 + 4.29 = 0.165T2
6.19 = 0.165T2
T2 = 37.5°C
Therefore, the new temperature of the piece of lead will be 37.5°C.
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