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olga_2 [115]
3 years ago
7

2.00 moles of an ideal gas was found to occupy a volume of 17.4 L at a pressure of 3.00 atm and at a temperature of 45 °C. Calcu

late the value of the gas constant 'R' in (Latm)/(molK)
Chemistry
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

R = 0.08208 L·atm/mol·K (based on data given)

Explanation:

PV = nRT => R = PV/nT

P = Pressure in atmospheres = 3.00 atm

V = Volume in Liters = 17.4 Liters

n = moles of substance = 2.00 moles

T = temperature in Kelvin = 45°C + 273 = 318K

R = (3.00atm)(17.4L)/(2.00mol)(318K) = 0.08208 L·atm/mol·K

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nata0808 [166]
<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

We are given that;

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Assuming the stadium would carry an equivalent number of atoms as people.

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Number of stadiums = Total number of atoms ÷ Number of atoms per stadium

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Thus, 1 × 10^18 atoms would occupy 1 × 10^13 stadiums

7 0
2 years ago
Express the ratio 1:<br><img src="https://tex.z-dn.net/?f=1%20%5Cfrac%7B1%20%7D%7B8%7D%20" id="TexFormula1" title="1 \frac{1 }{8
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Explanation:

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Answer:

\frac{9}{8}

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3 years ago
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3 years ago
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