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olga_2 [115]
3 years ago
7

2.00 moles of an ideal gas was found to occupy a volume of 17.4 L at a pressure of 3.00 atm and at a temperature of 45 °C. Calcu

late the value of the gas constant 'R' in (Latm)/(molK)
Chemistry
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

R = 0.08208 L·atm/mol·K (based on data given)

Explanation:

PV = nRT => R = PV/nT

P = Pressure in atmospheres = 3.00 atm

V = Volume in Liters = 17.4 Liters

n = moles of substance = 2.00 moles

T = temperature in Kelvin = 45°C + 273 = 318K

R = (3.00atm)(17.4L)/(2.00mol)(318K) = 0.08208 L·atm/mol·K

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Answer:

-O CH30

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What is the surface composition of planets in the solar system?
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A: Helium or Hydrogen

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2 years ago
An exacuted glass vessel weighs 50 g when empty, 148g when filled with an liquid of density o.989/cc and 50.5 g whenfilled with
Zanzabum

MW of gas : 124.12 g/mol

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

glass vessel wieight = 50 g

glass vessel + liquid = 148 ⇒ liquid = 148 - 50 =98 g

volume of glass vessel :

\tt V=\dfrac{m}{\rho}=\dfrac{98}{0.989}=99.1~ml

An ideal gas :

m = 50.5 - 50 = 0.5 g

P = 760 mmHg = 1 atm

T = 300 K

\tt PV=\dfrac{mass(m)}{MW}.RT\\\\MW=\dfrac{m.RT}{PV}\\\\Mw=\dfrac{0.5\times 0.082\times 300}{1\times 0.0991}=124.12~g/mol

3 0
3 years ago
How did the surface area of the metal strip expose to the solution affect the
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Answer:

See explanation below

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2 years ago
1. A smoothie contains 1 banana (B), 4 strawberries (St), 1 container of yogurt (Y), and 3 ice cubes (Ic). Write a balanced equa
kvv77 [185]

Answer:

1B +4St+1Y+3lc——-> BSt4Ylc3

Explanation:

I only know the answer for the first question.

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2 years ago
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