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olga_2 [115]
3 years ago
7

2.00 moles of an ideal gas was found to occupy a volume of 17.4 L at a pressure of 3.00 atm and at a temperature of 45 °C. Calcu

late the value of the gas constant 'R' in (Latm)/(molK)
Chemistry
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

R = 0.08208 L·atm/mol·K (based on data given)

Explanation:

PV = nRT => R = PV/nT

P = Pressure in atmospheres = 3.00 atm

V = Volume in Liters = 17.4 Liters

n = moles of substance = 2.00 moles

T = temperature in Kelvin = 45°C + 273 = 318K

R = (3.00atm)(17.4L)/(2.00mol)(318K) = 0.08208 L·atm/mol·K

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5 0
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3. If 90.0 grams of barium chloride react with sulfuric acid, how many
PtichkaEL [24]

Answer:

The answer to your question is 100.8 g

Explanation:

Data

  mass of Barium chloride = 90 g

  mass of Barium sulfate = ?

Balanced chemical reaction

    BaCl₂  +  H₂SO₄   ⇒    BaSO₄  +  2HCl

Process

1.- Calculate the molar mass of BaCl₂ and BaSO₄

BaCl₂ = 137.3 + (2 x 35.5) = 208.3g

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2.- Use proportions to find the mass of BaSO₄

              208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄

                90 g of BaCl₂    ---------------------   x

                              x = (90 x 233.3) / 208.3

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3.- Conclusion

There will be produced 100.8 g of BaSO₄          

4 0
2 years ago
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