2.00 moles of an ideal gas was found to occupy a volume of 17.4 L at a pressure of 3.00 atm and at a temperature of 45 °C. Calcu
1 answer:
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Answer:
This metal could be the aluminium with a specific heat of
Explanation:
A pie of unknown metal presents a mass (M) of 348 g. This metal is heated using energy (E) of 6.64 kJ and the temperature increases from T1 =24.4 to T2 =43.6°C. We can calculate the specific heat (H) of this metal as follows
We can replace previously presented data in this equation. After simplifying and converting to adequated units, we found that
Finally, the specific heat of this metal is
The aluminium could be the metal, its specific heat is similar to that found in this problem.
Finally, we can conclude that this metal could be the aluminium with a specific heat of
Answer:
The value of the partial pressure of the oxygen = 690 torr
Explanation:
Total pressure of the mixture of gases = 736 torr
The partial pressure of water vapor = 46 torr
From the law of pressure we know that
Total pressure = The partial pressure of water vapor + The partial pressure of oxygen
Put the values of pressures in above equation we get,
⇒ 736 = 46 +
⇒ = 736 - 46
⇒ = 690 torr
This is the value of the partial pressure of the oxygen.