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Alexus [3.1K]
4 years ago
14

Scientists made the following two observations about emission spectra: each element has a unique emission spectrum. atoms emit e

nergy only at specific wavelengths. describe how the bohr model explains both of these observations.
Chemistry
2 answers:
kondaur [170]4 years ago
3 0
<span>In the Bohr model electrons in atoms can occupy allowed orbits where they do not emit energy. Exchange of energy with the surrounding environment occurs only when an electron "jumps" from an orbit to another. Hope this answers the question. Have a nice day.</span>
Taya2010 [7]4 years ago
3 0

In the Bohr model, electrons can exist only in certain energy levels surrounding the atom.When electrons jump from a higher energy level to a lower one, they emit light at a wavelength that corresponds to the energy difference between the levels.The energy levels in each atom are unique.

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The reaction of 9.50 g of carbon with Excess O2 Yield 12.8 of CO2. What is the percent yield of this reaction?
Anna [14]

Answer:

Percentage yield = 36.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C + O₂ —> CO₂

Next, we shall determine the mass of C that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 13 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Next, we shall determine the theoretical yield of CO₂. This can be obtained as follow:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Therefore, 9.50 g of C will react to produce = (9.50 × 44) / 12 = 34.83 g of CO₂.

Thus, the theoretical yield of CO₂ is 34.83 g.

Finally, we shall determine the percentage yield of the reaction. This can be obtained as follow:

Actual yield of CO₂ = 12.8

Theoretical yield of CO₂ = 34.83 g

Percentage yield =?

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 12.8 / 34.83 × 100

Percentage yield = 1280 / 34.83

Percentage yield = 36.75%

5 0
3 years ago
Does xenon react with nitrogen and explain why
KiRa [710]
No, xenon will not react on Nitrogen because xenon only reacts with oxygen and fluorine. Xenon only reacts with the 2 elements because these 2 elements contain a strong electronegative element which is high in energy barrier that can move the electrons inside xenon elements.  Xenon is an element with a symbol of Xe, it is odorless and colorless gas. Common uses of xenon are flash lamps and arc lamps. Xenon is a luminous element, it glows when placed near to high voltage electric field.
4 0
3 years ago
Why is it important to calibrate your pipet before beginning an experiment?
den301095 [7]

Answer:

To ensure provide and reliable data

Explanation:

Calibration ensures precise repeatable performance while preventing pipetting errors. Just the way measurement standards are established to distinguish valid and invalid processes, pipette calibration standards are designed to ensure the best pipette accuracy.

3 0
3 years ago
Read 2 more answers
What is the name of the compound CH4?<br>​
agasfer [191]

Answer:

Methane

Explanation:

8 0
3 years ago
Determine the change in entropy for 2.7 moles of an ideal gas originally placed in a container with a volume of 4.0 L when the c
olchik [2.2K]

Answer:

The value of entropy change for the process dS = 0.009 \frac{KJ}{K}

Explanation:

Mass of the ideal gas = 0.0027 kilo mol

Initial volume V_{1} = 4 L

Final volume V_{2} = 6 L

Gas constant for this ideal gas ( R ) = R_{u}  M

Where R_{u} = Universal gas constant = 8.314 \frac{KJ}{Kmol K}

⇒ Gas constant R = 8.314 × 0.0027 = 0.0224 \frac{KJ}{K}

Entropy change at constant temperature is given by,

dS = R  log _{e} \frac{V_{2}}{V_{1}}

Put all the values in above formula we get,

dS = 0.0224  log _{e} [\frac{6}{4}]

dS = 0.009 \frac{KJ}{K}

This is the value of entropy change for the process.

6 0
3 years ago
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