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iren2701 [21]
4 years ago
9

How many moles of Na2Cr2O7 contain 14 moles of oxygen atoms?

Chemistry
2 answers:
sergiy2304 [10]4 years ago
7 0
The number of moles of sodium dichromate from the number of moles of oxygen atoms can be determined through stoichiometry. Using the molecular formula of the compound, Na2Cr2O7, 1 mole of the compound contains 7 moles of oxygen. Hence, 14 moles O2*(1 mole Na2Cr2O7/ 7 mole O2) is equal to 2 moles <span>Na2Cr2O7.</span>
Taya2010 [7]4 years ago
4 0

<u>Answer:</u> The number of moles of the compound are 2 moles.

<u>Explanation:</u>

We are given:

Moles of oxygen atom = 14 moles

The chemical formula for the given compound is Na_2Cr_2O_7

In 1 mole of sodium dichromate, 2 moles of sodium atoms, 2 moles of chromium atoms and 7 moles of oxygen atoms are present.

To calculate the moles of compound, we use unitary method:

7 moles of oxygen atoms are present in 1 mole of sodium dichromate.

So, 14 moles of oxygen atoms will be present in \frac{1}{7}\times 14=2mol of sodium dichromate.

Hence, the number of moles of the compound are 2 moles.

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Net ionic equation:

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Explanation:

Chemical equation:

K₂CO₃  +   CaCl₂    →   KCl  +  CaCO₃

Balance chemical equation:

K₂CO₃(aq)  +   CaCl₂(aq)    →   2KCl(aq)  +  CaCO₃(s)

Ionic equation:

2K⁺(aq) + CO²⁻₃(aq)  +   Ca⁺²(aq)  + 2Cl⁻(aq)  →   2K⁺(aq) + 2Cl⁻(aq)  + CaCO₃(s)

Net ionic equation:

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The K⁺(aq) and Cl⁻ (aq) are spectator ions that's why these are not written in net ionic equation. The CaCO₃ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equatio n.

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