1. On this graph, what is the change in velocity between 5 seconds and 8 seconds?
1 answer:
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Answer:
Explanation:
given,
velocity of particle 1 = 0.741 c to left
velocity of second particle = 0.543 c to right
relative velocity between the particle = ?
for the relative velocity calculation we have formula
u_x = 0.543 c
v_x = - 0.741 c
Relative velocity of the particle is
Answer:
a) w = 2.57 rad / s , b) α = 3.3 rad / s²
Explanation:
a) Let's use the conservation of mechanical energy, we will write it in two points the highest and when touching the ground
Initial. Higher
Em₀ = U = m g h
Final. Touching the ground
= K = ½ I w²
How energy is conserved
Em₀ =
mg h = ½ I w2
The moment of specific object inertia
I = m L²
We replace
m g h = ½ (mL²) w²
w² = 2g h / L²
The height of the object is the length of the bar
h = L
w = √ 2g / L
w = √ (2 9.8 / 2.97)
w = 2.57 rad / s
b) the angular acceleration can be found from Newton's second rotational law
τ = I α
W L = I α
mg L = (m L²) α
α = g / L
α = 9.8 / 2.97
α = 3.3 rad / s²
Answer:
22J
Explanation:
Given :
radius 'r'= 3cm
rotational inertia 'I'=4.5 x kgm²
mass on one side of rope ''= 2kg
mass on other side of rope'' =4kg
velocity'v' of mass ' = 2m/s
Angular velocity of the pulley is given by
ω = v /r => 2/ 3x
ω = 66.67 rad/s
For the rotating body, we have
KE = I ω²
= 10J
Next is to calculate kinetic energy of the blocks :
=12J
Therefore, the total kinetic energy will be
KE = =10 + 12
KE= 22J