The distance between Mars and the Sun in the scale model would be 1140 m
Explanation:
In this scale model, we have:
represents an actual distance of

The actual distance between Mars and the Sun is 228 million km, therefore

On the scale model, this would corresponds to a distance of
.
Therefore, we can write the following proportion:

And solving for
, we find:

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Explanation:
that's impossible,the radius of the earth can't decrease when the mass doubles!
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Answer:
Explanation:
When the craft was stationary , weight will be balanced by tension
T = mg
T = 7000 N
A)
when the craft was being lowered to the seafloor
drag force will act in upper direction , so
T₁ + 1800 = mg
T₁ = mg - 1800
= 7000 - 1800
= 5200 N
52 X 10² N
B)
when the craft was being raised from the seafloor , Tension will act in downward direction
T₂ = mg+ 1800
T₂ = 7000 - 1800
= 8800N
Efficiency = 1000/2000 = 0.5 = 50%