The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
<h3>
What are we to consider in equilibrium ?</h3>
Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.
Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.
The acceleration at which they will both move will be;
a = (
- 
) / ( + )
a = (5.75 - 3.53) / (5.75 + 3.53)
a = 2.22 / 9.28
a = 0.24 m/s²
Let us assume that the second mass starts from rest, and the distance covered is the h = 2.47 m
We can use third equation of motion to calculate the speed of mass 2 after it has moved ℎ=2.47 meters.
v² = u² + 2as
since u =0
v² = 2 × 0.24 × 2.47
v² = 1.1856
v = √1.19
v = 1.0888 m/s
Therefore, the speed of mass 2 after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
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Absolutely ! If you have two vectors with equal magnitudes and opposite
directions, then one of them is the negative of the other. Their correct
vector sum is zero, and that's exactly the magnitude of the resultant vector.
(Think of fifty football players pulling on each end of the rope in a tug-of-war.
Their forces are equal in magnitude but opposite in sign, and the flag that
hangs from the middle of the rope goes nowhere, because the resultant
force on it is zero.)
This gross, messy explanation is completely applicable when you're totaling up
the x-components or the y-components.
Work is done when the ‘object moves in the same direction as the force’ an example being a man walking up a flight of stairs carrying a box of weight.
Work is not done when the direction of the applied force and the direction in which the object moves are PERPENDICULAR to each other. An example being A man carrying a load while walking, no work is done on the load in the upward direction as the load is only moving horizontally.
Thus the answer is whenever she pulls the puppy towards her
Answer:
f = c / λ
Explanation:
Electromagnetic waves are types of periodic waves. They propagate with the same speed as light (3 * 10⁸ m/sec).
Therefore:
velocity of wave = c
Now, the equation that relates speed of wave and its frequency is as follows:
c = λf
where:
c is the speed of wave
f is the frequency of the wave
λ is the wavelength of the wave
Solve the above equation for frequency, we will end up with:
f = c / λ
D. They showed that the atoms have a dense nucleus. Rutherford put Thomson's <span>hypothesis to test by devising a "gold foil" experiment, he figured that if Thomson's model was correct then the mass of the atom was spread out throughout the atom. If he shot high velocity alpha particles (helium nuclei) at an atom there would be very little to deflect the alpha particles. He tested this with a thin film of gold atoms, finding that most alpha particles went directly through the gold foil but, a few alpha particles rebounded backwards, which was</span><span> not consistent with Thomson's model. He was forced to discard this model and reasoned that the only way the alpha particles could be deflected backwards was if most of the mass in an atom was concentrated in a nucleus.</span>
