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2 years ago

Why will a struck tuning fork sound louder when it is held against a table?.

1 answer:

7 0

Answer:
1.)the surface of the table is set into vibration
2.)the initial vibration was larger
3.)The entire table vibrates

Explanation:hope this helps :3 have a good day xlXCherryColaXlx..(pls mark me brainliest)

You might be interested in

PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works

steposvetlana [31]

Solved your another question same like this with scaling to Cm this time we go with metre(m)

Scale factor

1km=10³m
1m=10^{-3}km

Mercury

58000m

Ven us

108000m

Earth

150000m

Mars

228000m

Jupiter

778000m

Saturn

1430000m

Uranus

2870000m

Neptune

4500000m

7 0

2 years ago

One gram of Uranium averages release 1.01 KJ (10^7) of energy. How much mass could be converted to energy to release this much e

frutty [35]

Answer:

The amount of mass that needs to be converted to release that amount of energy is $1.122 X 10^{-7} kg$

Explanation:

From Albert Einstein's Energy equation, we can understand that mass can get converted to energy, using the formula

$E= \Delta mc^{2}$

where $\Delta m$ = change in mass

c = speed of light = $3 \times 10 ^{8}m/s$

Making m the subject of the formula, we can find the change in mass to be

$\Delta m = \frac{E}{c^{2}}= \frac{1.01 \times 10^{3} \times 10^{7}}{(3 \times 10^{8})^{2}}= 1.122 \times 10 ^{-7}kg$

There fore, the amount of mass that needs to be converted to release that amount of energy is 1.122 X 10 ^-7 kg

5 0

3 years ago

A building is 512 m high. What must be the minimum water pressure in a pipe at ground level in order to get water out of a tap i

vivado [14]

Answer:

Pressure = 5 x 10⁶ Pa

Explanation:

Given:

Height of building = 512 m

Find:

Pressure

Computation:

P2 = P1+dgh

P2 = 1 + (1000)(9.8)(512)

P2 = 51.2 atm

Pressure = 5 x 10⁶ Pa

6 0

3 years ago

If the radius of a blood vessel drops to 84.0% of its original radius because of the buildup of plaque, and the body responds by

erma4kov [3.2K]

To develop this problem it is necessary to apply the equations concerning Bernoulli's law of conservation of flow.

From Bernoulli it is possible to express the change in pressure as

$\Delta P = \frac{1}{2}\rho (v_1^2-v_2^2)+ \rho g (h_1h_2)$

Where,

$v_i =$ Velocity

$\rho =$ Density

g = Gravitational acceleration

h = Height

From the given values the change of flow is given as

$R = r^4P$

Therefore between the two states we have to

$\frac{R_2}{R_1} = \frac{r_2^4 P_2}{r_1^4 P_1} *100\%$

$\frac{R_2}{R_1} = \frac{84^4 (110)}{100^4*(100)} *100\%$

$\frac{R_2}{R_1} = 54.77\%$

The flow rate will have changed to 54.77 % of its original value.

4 0

2 years ago

Planet RMM-1 has a mass of 28,500 kg and the star it revolves around has

SOVA2 [1]

Gravitational force = G · (mass₁) · (mass₂) / (distance)

(distance²) = G · (mass₁) · (mass₂) / (Gravitational force)

G = 6.67 x 10⁻¹¹ n-m² / kg² (the "gravitational constant")

Distance² = (6.67 x 10⁻¹¹ n-m² / kg²) (28,500 kg) (2.2 x 10⁸ kg) / (39 N)

Distance² = (6.67 · 28,500 · 2.2 x 10⁻³ N-m²) / (39N)

Distance² = (418.209 N-m²) / (39N)

Distance² = 10.72 m²

Distance = 3.275 meters

An absurd scenario, but that's by golly what the math says with the numbers provided. I guess it's a teeny tiny planet orbiting 3.275 meters outside a teeny tiny black hole.

3 0

3 years ago