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wolverine [178]
3 years ago
10

A horizontal spring with spring constant 950 N/m is attached to a wall. An athlete presses against the free end of the spring, c

ompressing it 7.0 cm. How hard is the athlete pushing?
Physics
1 answer:
OLga [1]3 years ago
4 0

Answer:

66.5N

Explanation:

F = kx

Where F = force

K = spring constant

x = compression

Given

K = 950N/m

x = 7.0cm

F = ?

First convert the compression to meters .

7.0cm = 7.0 x 0.01

= 0.07 meters

Therefore

F = 950 x 0.07

= 66.5N

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Vesna [10]

Answer:

The mass of the bullet is 15 g.

(b) is correct option.

Explanation:

Given that,

Momentum = 2.8 kg m/s

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Using formula of momentum

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