Answer:
6.77 m/s
Explanation:
Acceleration = Force/mass;
The block is accelerated by 13/6.4 m/s^2 for 2.1s from an initial velocity of 2.5m/s.
Applying the equation of motion:
Vf=Vi + at
Where Vf is the final velocity, Vi is the initial velocity, a is the acceleration and t is the time for which the object accelerates.
<h3>Vf= 2.5 + ((13/6.4)*2.1);</h3>
Answer:
Wy = - 268.3*cos(42) = - 199.38 [N]
Wx = 268.3*sin(42) = 179.52 [N]
Explanation:
To solve this problem we must make a free body diagram, in the attached image we can see a free body diagram.
Taking the inclined X & y axes with the same angle of 42°, we can see that the weight can be decomposed on both axes.
Since the angle is adjacent to the y-axis, we can use the cosine function
Wy = - 268.3*cos(42) = - 199.38 [N]
Wx = 268.3*sin(42) = 179.52 [N]
Answer:
For a gas held at constant temperature, we can apply Boyle's law, which states that the product between the gas pressure and its volume is constant:

where
P is the pressure
V is the volume
As we see from the equation, P and V are inversely proportional to each other: this means that when the volume is decreased, the pressure increases, and vice-versa. The reason for that is that when the volume is decreased, the gas is compressed, so the molecules of the gas come closer to each other, so they collide more frequently with the wall of the container, exerting therefore a greater pressure.
Answer:
Explanation:
Maximum vertical distance or height = h = 35.4 m
let's consider the initial speed at the top is zero.
As the roller coaster is coming from top to bottom there is the conversion of gravitational potential energy into kinetic energy. So we will consider the law of conservation of energy.
As in this case,
Loss in potential energy = Gain in Kinetic energy
mgh = 1/2mv²
mass will cancel out will mass.
gh = 1/2 v²
v = √2gh
v = √2×9.8×35.4
v =√693.84
v = 26.34 m/s
The rollar coaster will have the maximum speed of 26.34 m/s when it reaches the bottom if we ignore the frictional forces.