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12345 [234]
3 years ago
15

What is the element with 107 electrons

Physics
2 answers:
grigory [225]3 years ago
6 0

Answer:

Bohrium has exactly 107 electrons

Maurinko [17]3 years ago
4 0

Answer: Bohrium (please make me Brainliest)

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How many grams are 2.5 x 10^23 molecules of mg
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2.5e+20 grams is the right answer
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3 years ago
Which of the following is NOT a likely result of regular physical activity?
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Answer:

B: Decreased attention span is the answer.

Explanation:

Just took the test on e d g e n u i t y.

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3 years ago
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An object with a density of 0.85 g/cc is dropped into each of the two beakers shown below. Beaker 1 has a density of 0.5 g/cc. B
Oliga [24]

Answer:

The object will sink in the liquid in beaker 1.

The object will float in the liquid in beaker 2

Explanation:

The density of an object relative to the density of a fluid determines if the object floats or sink in a fluid. The density of a material is the measure of the amount of mass of that material packed into a unit volume of that material.

For the beaker 1, the liquid in this beaker has a density of 0.5 g/cc, which is lesser than the density of the object (0.85 g/cc). This means that the object will add more mass than there should be to the volume of the space it displaces within the field. This results in the object sinking in the fluid.

For beaker 2, the liquid in this beaker has a density of 1 g/cc, which is more than the density of the object (0.85 g/cc). This means that the object will add less mass than there should be to the volume of the space it displaces within the field. This results in the object floating in the fluid.

8 0
4 years ago
A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi
docker41 [41]
<span>32 mph
   First, let's calculate the location of the particle at t=1, and t=4
 t=1
 s = 6*t^2 + 2*t
 s = 6*1^2 + 2*1
 s = 6 + 2
 s = 8 t = 4
 s = 6*t^2 + 2*t s = 6*4^2 + 2*4
 s = 6*16 + 8
 s = 96 + 8
 s = 104
   So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
 avg_vel = (104-8)/(4-1) = 96/3 = 32
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6 0
3 years ago
Consider two planets of mass m and 2m,
Rzqust [24]

Answer:

Part a)

\frac{F_1}{F_2} = 10.125

Part b)

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

\frac{T_1}{T_2} = 9.54

Explanation:

Part a)

As we know that the gravitational force is given as

F = \frac{GMm}{r^2}

so we will have to find the ratio of force on two planets due to star

so here we have

\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}

\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}

\frac{F_1}{F_2} = 10.125

Part b)

Orbital speed is given as

v = \sqrt{\frac{GM}{r}}

so the ratio of two orbital speed is given as

\frac{v_1}{v_2} = \frac{r_2}{r_1}

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

Time period is given as

T = 2\pi\sqrt{\frac{r^3}{GM}}

so the ratio of two time period is given as

\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}

\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}

\frac{T_1}{T_2} = 9.54

8 0
3 years ago
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