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2 years ago

55 Points ££which state of matter can undergo three types of thermal expansion

Physics

2 answers:

bija089 [108]2 years ago

7 0

Answer:

The three types of thermal expansions are Linear expansion , Superficial expansion and Cubical expansion

CaHeK987 [17]2 years ago

5 0

In my knowledge 

Your answer is Gases

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How does an atom of chlorine-37 become a chloride ion with a -1 charge?

kirill115 [55]

Answer:

B. The atom gains 1 electron, to make a total of 18 electrons.

Explanation:

Chlorine is the 17th element in the periodic table, so it has atomic number 17:

Z = 17

This means that a neutral atom of chlorine has 17 protons and 17 electrons.

When a chlorine atom gains 1 electron, its electric charge (initially zero) becomes -1, since the electron has negative charge of -1 (in elemntary charge units). This also means that the number of electrons in the ion is now

17 + 1 = 18

So the correct answer is

B. The atom gains 1 electron, to make a total of 18 electrons

5 0

3 years ago

True or False An object will slow down and stop as long as no forces act upon it

My name is Ann [436]

Answer:

false

Explanation:

Understand Newton’s first law of motion. Experience suggests that an object at rest will remain at rest if left alone, and that an object in motion tends to slow down and stop unless some effort is made to keep it moving. An object will go on forever if there were no forces to act upon it. In space, a rocket will go forever at the speed it projects.

5 0

2 years ago

Read 2 more answers

Three point charges are arranged along the x axis. Charge q1=-4.00nC is located at x= .250 m and q2= 2.40 nC is at the x= -.300m

Umnica [9.8K]

Answer:

q₃=5.3nC

Explanation:

First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:

$F= k\frac{|q_aq_b|}{r^{2} } \\\\\\F_{13}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(-4.00*10^{-9}C)q_3|}{(.250m)^{2} } =576q_3N/C\\\\F_{23}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(2.40*10^{-9}C)q_3|}{(.300m)^{2} } =240q_3N/C\\$

Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:

$F_{Net}=F_{13}+F_{23}\\\\4.40*10^{-9} N=576q_3N/C+240q_3N/C\\\\4.40*10^{-6} N=816q_3N/C\\\\\implies q_3=5.3*10^{-9}C=5.3nC$

In words, the value of q₃ must be 5.3nC.

7 0

2 years ago

a 60g tennis ball travelling at 30m/s hi a wall and bounce back at 20m/s.calculate (a)momentum of the ball before impact (b)mome

frez [133]

Explanation:

the formula for momentum is denoted by p=mv where p is momentum, m is mass and v is velocity. thus, the velocity before impact would be 0.060 x 30 = 1.8 kg/ms

the second one would just be 0.060 x 20 0.72kg/ms

I'm not 100 percent sure this is correct but yeah

6 0

2 years ago

The electric force on object A by object B is F. If the charge of object B were only half as large as it is, but everything else

nalin [4]

Answer:

The new electric force on object B by object A is one half of the magnitude of the original force F, in the opposite direction. Equals -F/2

Explanation:

We are asked to demonstrate what happens when you reduce the magnitude of the charge of an object in an interactive system.

Assumptions.

The new force is F'

The system is isolated from other external interferences

The distance between objects A and B remains unchanged

Analysis.

The force F on object A by object B is given by the formula

F=(k*q,a*q,b)/d^2

where k is the Coulomb's Law constant, and equals 9x10^9 N/m s

q,a and q,b equals the original charges of objects A and B

d is the distance between objects A and B

Now, we are to calculate the new force, let's call it F', and following the same reasoning.

F'=(k*q',a*q',b)/d'^2

Given that only q', b is different to the original, we have that

F'=(k*q,a*q',b)/d^2

Now, q',b=q,b/2 and replacing

F'=(k*q,a*q,b)/(2*d^2)

Now we find the relation between F' and F

F'/F=[(k*q,a*q,b)/(2*d^2)]/[(k*q,a*q,b)/d^2]

Reducing similar terms

F'/F=1/2

However, we should also consider that the forces F and F' are in oposite directions, so simplifying the vectorial notation,

F'/F=-1/2, meaning that F'=-F/2

7 0

2 years ago

55 Points ££which state of matter can undergo three types of thermal expansion​

55 Points ££which state of matter can undergo three types of thermal expansion