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Phantasy [73]
1 year ago
11

How many moles are in 1.20 times 10^25 atoms of phosphorus

Chemistry
1 answer:
Stels [109]1 year ago
5 0

19.927 moles are in 1.20 times 10^{25} atoms of phosphorus.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 ×10^{23} of some chemical unit, be it atoms, molecules, ions, or others.

1 mole of any substance contain Avogadro's number of molecules so we can calculate the number of moles by dividing the provided number of atoms over Avogadro's number to obtain the number of moles .

Moles= \frac{Atoms}{\;Avogadro's \;number }

Moles=  1.20 X 10^{25} atoms ÷ 6.022 X 10^{23}

= 19.927

Hence, 19.927 moles are in 1.20 times 10^{25} atoms of phosphorus.

Learn more about moles here:

brainly.com/question/26416088

#SPJ1

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What is the difference between ionic compund and covalent compound​
sleet_krkn [62]

A covalent bond is formed between two non-metals that have similar electronegativities.

An <em>i</em><em>o</em><em>n</em><em>i</em><em>c</em><em> </em><em>b</em><em>o</em><em>n</em><em>d</em> is formed between a metal and a non-metal. Non-metals(-ve ion) are "stronger" than the metal(+ve ion) and can get electrons very easily from the metal. These two opposite ions attract each other and form the ionic bond.

5 0
3 years ago
Consider the following reaction: C6H6 + O2 \longrightarrow ⟶ CO2 + H2O 39.7 grams of C6H6 are allowed to react with 105.7 g of O
Ivenika [448]

Answer:

116.3 grCO2

Explanation:

1st - we balance the equation so that it finds the same amount of elements of the product side and of the reagent side

C6H6 +15/2 O2⟶ 6CO2 +3 H2O

2nd - we calculate the limiting reagent

39.2gr C6H6*(240grO2/78grC6H6)=120 grO2

we don't have that amount of oxygen so this is the excess reagent and oxygen the limiting reagent

3rd - we use the limiting reagent to calculate the amount of CO2 in grams

105.7grO2*(264grCO2/240grO2)=116.3 grCO2

7 0
2 years ago
Bugaboo can be oxidised to a carboxylic acid by heating with acidified potassium manganate (VII). Give the name and structural f
Novosadov [1.4K]

Answer:

See below.

Explanation:

CH3CH2CH2CH2OH is butanol.

The carboxylic acid formed , butyric acid has the formula:

CH3CH2CH2COOH.

Structural formula:

       H     H    H       O                  

        |       |      |        ||                      

H  -  C  -  C  -  C   -  C  -  OH

       |       |       |    

      H     H     H

8 0
3 years ago
If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
Nikolay [14]

Answer:

0.036 M of CH_{3} COOH

Explanation:

It is an example of acid-base neutralization reaction.

KOH  + CH_{3} COOH  ----> CH_{3} COO^{-} K^{+}   +   H_{2}O

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= \frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

M_{1}V_{1} =M_{2}V_{2}------------------------------(1)

where

M_{1}= Molarity of Acid

V_{1}= Volume of Acid

M_{2}= Molarity of Base

V_{2}= Volume of Base

M_{1}=0.3330 M

V_{1}=10.62 mL

V_{2}=98.2 mL

M_{2}=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =M_{2}  × 98.2  

M_{2}=\frac{0.3330*10.62}{98.2}

M_{2}=0.036 M

3 0
2 years ago
!!!!!!!!!!!!!!!????<br> hElP!!!!!!!!!!!!
kakasveta [241]
I think the answer is transparent and translucent
5 0
3 years ago
Read 2 more answers
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