The number of moles of the magnesium (mg) is 0.00067 mol.
The number of moles of hydrogen gas is 0.0008 mol.
The volume of 1 more hydrogen gas (mL) at STP is 22.4 L.
<h3>
Number of moles of the magnesium (mg)</h3>
The number of moles of the magnesium (mg) is calculated as follows;
number of moles = reacting mass / molar mass
molar mass of magnesium (mg) = 24 g/mol
number of moles = 0.016 g / 24 g/mol = 0.00067 mol.
<h3>Number of moles of hydrogen gas</h3>
PV = nRT
n = PV/RT
Apply Boyle's law to determine the change in volume.
P1V1 = P2V2
V2 = (P1V1)/P2
V2 = (101.39 x 146)/(116.54)
V2 = 127.02 mL
Now determine the number of moles using the following value of ideal constant.
R = 8.314 LkPa/mol.K
n = (15.15 kPa x 0.127 L)/(8.314 x 290.95)
n = 0.0008
<h3>Volume of 1 mole of hydrogen gas at STP</h3>
V = nRT/P
V = (1 x 8.314 x 273) / (101.325)
V = 22.4 L
Learn more about number of moles here: brainly.com/question/13314627
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The charge on Pb in Pb(SO3)2 is Lead (IV) Sulfite.
<span><em><u>Climatology </u>is a <u>subspecialty </u>of a </em><u><em>Climate</em></u><em> and for how the <u>climate</u> changes. This is averaged out from over a set of a period of time.
<u>I hope this helps! ;D</u></em></span>
They can be stopped by a piece of paper.
The answer is V = 0.6 L
The explanation:
1- First we will get P (H) :
p (H) = p total - p (H2O)
= 752 mmHg - 18.65 mmHg
= 733 mmHg
= 733 mmHg X (1 atm / 760 atm) = 0.964 atm
2- then when the reaction equation is:
Zn(s)+2HCl(aq) -> H2(g)+ZnCl2(aq)
so, then 1 mole of Zn will produce 1 mole of H2.
so, we need to get first the mole of Zn:
mole Zn = mass / molar mass
= 1.566g / 65.38g/mol
= 0.02395mol
∴ 0.02395 mol of Zn will produce 0.02395 mol of H2
by using the ideal gas equation we can get the volume V :
when :
PV = nRT
when T is the temperature = 21 + 273 = 294 K
and R is the ideal gas constant = 0.0821 L atm /K mol
and n is the number of moles = 0.2395 mol
and P is the pressure = 0.964 atm
so, by substitution:
V = (0.02395 moles H2)(0.0821 L atm / K mole)(294 K) / (0.964 atm)
= 0.6 L