Question

The interhalogen ClF₃ is prepared in a two-step fluorination of chlorine gas:Cl₂(g) + F₂(g) ⇄ CIF(g) CIF(g) + F₂(g) ⇄ CIF₃(g)(a) Balance each step and write the overall equation.

Answer 1

The interhalogen CIF3 is prepared in a two-step fluorination of chlorine gas : Cl₂(g) + F₂(g) ⇄ CIF(g) CIF(g) + F₂(g) ⇄ CIF₃(g). The balanced equation will be

           Cl₂(g) + 2F₂(g) ⇌ ClF(g) + CIF₃(g)

Solution:

These are the two equation

Cl 2(g)+F 2(g) ⇌ ClF(g)                             (1)

ClF(g)+F 2 (g) ⇌ ClF 3 (g)                         (2)

Balance equation one

      Cl 2(g)+F 2(g) ⇌ ClF(g)                        

This will be the result

      Cl 2 (g)+F 2 (g)⇌2ClF(g)

Balance equation two

      ClF(g)+F 2 (g)⇌ClF 3 (g)

The equation is already balanced

On adding both the equation the result will be

Cl 2 (g)+2F 2(g) ⇌ ClF(g)+ClF 3 (g)

​

To learn more click the given link

brainly.com/question/11904811

#SPJ4

​