The interhalogen CIF3 is prepared in a two-step fluorination of chlorine gas : Cl₂(g) + F₂(g) ⇄ CIF(g) CIF(g) + F₂(g) ⇄ CIF₃(g). The balanced equation will be
Cl₂(g) + 2F₂(g) ⇌ ClF(g) + CIF₃(g)
Solution:
These are the two equation
Cl 2(g)+F 2(g) ⇌ ClF(g) (1)
ClF(g)+F 2 (g) ⇌ ClF 3 (g) (2)
Balance equation one
Cl 2(g)+F 2(g) ⇌ ClF(g)
This will be the result
Cl 2 (g)+F 2 (g)⇌2ClF(g)
Balance equation two
ClF(g)+F 2 (g)⇌ClF 3 (g)
The equation is already balanced
On adding both the equation the result will be
Cl 2 (g)+2F 2(g) ⇌ ClF(g)+ClF 3 (g)
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