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1 year ago

If you add sucrose to catalase when testing for reactivity, do you expect to see a reaction?.

Chemistry

1 answer:

pav-90 [236]1 year ago

8 0

There is no reaction when you add catalase to sucrose.

<h3>What is sucrose?</h3>

Sucrose is a disaccharide that consist of glucose and fructose. Both glucose and fructose are hexoses.

Owing to the fact that catalase is specific to sucrose, there is no reaction when you add catalase to sucrose.

Learn more about sucrose:brainly.com/question/24214907

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9.27 mol of oxygen is equal to______molecules of oxygen <br> Please help I need it

bixtya [17]

<h3>Answer:</h3>

5.58 × 10²⁴ molecules O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

9.27 mol O₂ (Oxygen)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 9.27 \ mol \ O_2(\frac{6.022 \cdot 10^{23} \ molecules \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 5.58239 \cdot 10^{24} \ molecules \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules. We are given 3 sig figs.</em>

5.58239 × 10²⁴ molecules O₂ ≈ 5.58 × 10²⁴ molecules O₂

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2 years ago

4. Jake surveyed his 25 classmates on their favorite flavor of

Eddi Din [679]

Answer:

Explanation:

In total there are 25 students. If you add up all the other students who liked flavors other than strawberry twist you will get 14. That means 14/25 students did not favor strawberry twist, while the other 11/25 did.

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2 years ago

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schepotkina [342]

Answer: not sure either. not sure what exactly your asking because the wording is weird. (no offense)

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2 years ago

Calculate the gravitational force of attraction between a 26kg boy and his 5.1kg dog when they are separated by 0.19m

Pavel [41]

Answer:

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

Explanation:

Given:

Mass M1 = 26 kg

Mass M2 = 5.1 kg

Distance r = 0.19 m

Find:

Gravitational force of attraction G(f)

Computation:

Gravitational force of attraction G(f) = G(m1)(m2)/r²

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