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amid [387]
2 years ago
7

Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube

from the Bunsen burner, there are 6 mL of water left in the test tube. This experiment is a good example of a
chemical change involving phase changes.
physical change involving phase changes.
physical change involving chemical reactions.
chemical change involving chemical reactions.
Chemistry
2 answers:
Marat540 [252]2 years ago
8 0

physical change involving phase changes

monitta2 years ago
6 0
Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube from the Bunsen burner, there are 6 mL of water left in the test tube. This experiment is a good example of a <span>physical change involving phase changes. </span>
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8. If the temperature of a piece of steel decreases, what happens to its density?
Verdich [7]

Answer:

I think the answer is the 3rd one

3 0
2 years ago
Write the balanced equation for a reaction between aqueous nitric acid (HNO3) and solid lithium metal (this is a single replacem
Lemur [1.5K]

<u>Answer:</u> The equation is given below.

<u>Explanation:</u>

Single replacement reactions are the chemical reactions in which more reactive metal displaces a less reactive metal from its chemical reaction. General equation for these reactions is given by the equation:

A+BC\rightarrow AC+B

Metal A is more reactive than metal B.

The reactivity of metals is judged with the help of reactivity series. In this series, the metals lying above are more reactive than the metals which lie below in the series.

For the reaction of solid lithium metal and nitric acid, the equation follows:

3Li(s)+4HNO_3(aq.)\rightarrow 3LiNO_3(aq.)+2H_2O(l)+NO(g)

This is a type of single replacement reaction because Lithium (more reactive metal) is replacing Hydrogen (less reactive metal) from the chemical reaction.

3 0
3 years ago
How many significant digits does the number 700 have?
OLga [1]

Answer: 700 has one significant figure which is 7.

Explanation: These are some rules for significant figures

•All non-zero digits are significant: 1,2,3,4,5,6,7,8,9

•Zero between non-zero digits are significant: They are three significant figures in 203.

•Leading zeros are not significant: There are two significant figures in 0.56.

•Trailing zero to the right of decimal are significant. There are four significant figures in 62.00

•Trailing zeros in a whole number with the decimal shown are significant: This makes "700." three significant figures.

•Trailing zeros in a whole number with no decimal shown are not significant: This makes 700 one significant figure.

5 0
3 years ago
Read 2 more answers
What can create sediment
bearhunter [10]
Sediment is created by wind and water.

4 0
3 years ago
Read 2 more answers
A 1.50 L buffer solution is 0.250 M in HF and 0.250 M in NaF. Calculate the pH of the solution after the addition of 0.100 moles
alexgriva [62]

Answer : The pH of the solution is, 3.41

Explanation :

First we have to calculate the moles of HF.

\text{Moles of HF}=\text{Concentration of HF}\times \text{Volume of solution}

\text{Moles of HF}=0.250M\times 1.50L=0.375mol

Now we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.8\times 10^{-4})

pK_a=4-\log (6.8)

pK_a=3.17

The reaction will be:

                             HF+OH^-\rightleftharpoons F^-+H_2O

Initial moles     0.375     0.100   0.375

At eqm.   (0.375-0.100)      0     (0.375+0.100)

                     = 0.275                    = 0.475

Now we have to calculate the pH of solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[F^-]}{[HF]}

Now put all the given values in this expression, we get:

pH=3.17+\log [\frac{(\frac{0.475}{1.50})}{(\frac{0.275}{1.50})}]

pH=3.41

Thus, the pH of the solution is, 3.41

8 0
3 years ago
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