Ask question

Ask question

All categories

faltersainse [42]

1 year ago

10

The bar graph shows the numbers of reserved campsites at a campground for one week. What percent of the reservations were for Fr

iday or Saturday? Write the percent as a mixed number in simplest form.

1 answer:

natima [27]1 year ago

5 0

Answer:

3/2

Step-by-step explanation:

You might be interested in

Is .634 rational number

Ksivusya [100]

Yes 0.634 is a rational number.
Rational numbers are those numbers that can be still expressed in standard form or in fraction form and vice-versa. Unlike irrational numbers that are opposed to the definition of rational numbers. These values include pi, square root of two and etc. These values are impossible to fractionize. To better illustrate this circumstance.

We can have calculate a number that will have a quotient of 0.634 or a fraction that is equal to the given value. <span><span>
1. </span><span> 634/1000 = 0.634</span></span>
<span><span>2. </span><span> 317/500 = 0.634 </span></span>

3 0

2 years ago

What is 11 feet and 8 inches plus 2 feet and 9 inches

Agata [3.3K]

Answer:

14 feet and 5 inches

Step-by-step explanation:

11 feet + 2 feet= 13 feet

9 inches + 8 inches = 17 inches

17 inches = 1 foot and 5 inches

13 + 1 = 14 feet

5 inches + 0 inches = 5 inches

7 0

2 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

2 years ago

How Ro U Sovle This Problem Bc I Don't Know How?

marissa [1.9K]

You would have to transform the fractions to decimals by dividing. For the first one, if you divide 4 by 5 you get .8. To transform a decimal to percent you move the decimal place 2 times to the right or multiply by 100 (They both would give you the same thing)

3 0

2 years ago

Find the value of x <br> 5x+15+6x-10=180

lana [24]

Combine the common factors.

11x + 5 = 180

Subtract 5 from both sides.

11x = 175

Divide 11 from both sides to isolate the x.

x = 15.90909091

4 0

2 years ago

Read 2 more answers