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mixas84 [53]
3 years ago
6

Does the shape of molecule matter? why?​

Physics
2 answers:
Rudik [331]3 years ago
7 0

Answer:

Molecular shapes are important in determining macroscopic properties such as melting and boiling points, and in predicting the ways in which one molecule can react with another.

Explanation:

ZanzabumX [31]3 years ago
3 0

Yes, a shape of a molecule does matter.

The shape of a molecule helps to determine its properties.

For example, water molecules have a bent structure. This is one reason why water molecules are polar and have properties such as cohesion, surface tension and hydrogen bonding.

I hope this helps!

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Define malleability?<br>​
ad-work [718]

Answer:

Explanation:

the quality or state of being malleable: such as. a : capability of being shaped or extended by hammering, forging, etc. the malleability of tin.

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If the photon scatters in the backward direction, what is the magnitude of the linear momentum of the electron just after the co
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Momentum is a vector quantity, and is always conserved. Whenever a collision occurs between two objects, the objects behave under the principle of conservation of momentum. Therefore, if an object moves in the direction opposite to its original direction after a collision, then this indicates that the momentum of the colliding object was greater than the object under consideration. 
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A merry-go-round is spinning at a rate of 4.04.0 revolutions per minute. Cora is sitting 0.50.5 m from the center of the merry-g
dsp73

Answer:

angular speed of both the children will be same

Explanation:

Rate of revolution of the merry go round is given as

f = 4.04 rev/min

so here we have

f = \frac{4.04}{60} =0.067 rev/s

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\omega = 2\pi f

\omega = 2\pi(0.067)

\omega = 0.42 rad/s

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7 0
3 years ago
Please help! you are amazing! brainliest too!
german
I think it’s B hope it helps:)
6 0
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Read 2 more answers
A small space probe of mass 170 kg is launched from a spacecraft near Mars. It travels toward the surface of Mars, where it will
alukav5142 [94]

Answer:

The change  in momentum is  \Delta p =   kg \cdot m/s      

Explanation:

From the question we are told that  

       The mass of the probe is  m = 170 kg

       The location of the prob at time t = 22.9 s is  A  =

       The  momentum at time  t = 22.9 s is  p = < 51000, -7000, 0> kg m/s

        The net force on the probe is  F =  N

Generally the change in momentum is mathematically represented as

              \Delta p = F * \Delta t

The initial time is   22.6 s

 The final time  is  22.9 s

             Substituting values  

           \Delta p =  * (22.9 - 22.6)

            \Delta p =  * (0.3)  

              \Delta p =   kg \cdot m/s        

 

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