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mixas84 [53]
2 years ago
6

Does the shape of molecule matter? why?​

Physics
2 answers:
Rudik [331]2 years ago
7 0

Answer:

Molecular shapes are important in determining macroscopic properties such as melting and boiling points, and in predicting the ways in which one molecule can react with another.

Explanation:

ZanzabumX [31]2 years ago
3 0

Yes, a shape of a molecule does matter.

The shape of a molecule helps to determine its properties.

For example, water molecules have a bent structure. This is one reason why water molecules are polar and have properties such as cohesion, surface tension and hydrogen bonding.

I hope this helps!

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Please what is the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees ?
Tpy6a [65]

Answer:

No work is done since no distance is given

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

5 0
2 years ago
Which best describes the purpose of a controlled experiment?
navik [9.2K]
A controlled experiment is best described as a safe, in depth, and insightful display that helps you understand the purpose of the experiment better
3 0
3 years ago
You pull a rope to the left with 300n and a friend pulls it the rope to the right with 425n what is the magnitude and direction
eduard

Answer: from vector law opposite we minus

Hence

425n-300n=125n to the right

Hints in left vector have -Ve sign while right have +Ve sign

5 0
3 years ago
In what way do sound waves differ from radio waves?.
Akimi4 [234]
Radio waves are a type of electromagnetic wave that can travel when there is no medium, whereas sound waves are a type of mechanical wave that cannot travel if there is no medium
4 0
2 years ago
An electroscope has a charge of −2.0 µC while your finger has a charge of 2.7 µC. You touch the electroscope with your finger an
anyanavicka [17]

Answer:

1.39 × 10⁻¹³ electrons were transferred

Explanation:

Given:

Charge on electroscope = - 2.0 μC

charge on finger = 2.7 μC

Now,

The net charge when in contact

= Charge on electroscope + charge on finger

or

The net charge when in contact = - 2.0 μC + 2.7 μC = 0.7 μC

Also,

Charge on the electroscope and the finger is same

thus,

The charge on the electroscope = \frac{\textup{Net charge}}{\textup{2}}

or

The charge on the electroscope = \frac{0.7}{\textup{2}}

or

The charge on the electroscope = 0.35 μC

Now,

The change in charge on the electroscope

= Final charge - Initial charge on the electroscope

= 0.35 μC - (- 2.0 μC)

or

The change in charge on the electroscope = 2.35 μC

also,

Charge = Number of electrons × Charge on an electron

or

2.35 μC = Number of electron  × 1.69 × 10⁻¹⁹ C

or

2.35 × 10⁻⁶ C = Number of electron  × 1.69 × 10⁻¹⁹ C

or

Number of electron = \frac{\textup{2.35\times10^{-6}}}{\textup{1.69\times10^{-19}}}

or

Number of electron = 1.39 × 10⁻¹³ electrons were transferred.

6 0
2 years ago
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