Answer:
86MJ
Explanation:
THE TOPIC FROM WHICH THE QUESTION IS OBTAINED IS WORK, ENERGY AND POWER
- Power is defined as the time rate of doing work.
- Power =
- If the energy use is in joules and the time is in seconds, then power is a measure of watts.
1watt = 1 joule per second.
- According to the question, we need to find how much energy does one house use during each 24 hour day ( Already given time = 24hours) when the average rate of electric energy consumption in one house is 1.0 kW ( we have been given power = 1kW).
- Power = 1kW = 1 × 10³W
- Time = 24hours = 24 ×3600 = 86400seconds.
- It is important we have our time in seconds so as to be consistent with unit and dimension
Power =
1 × 10³W =
- Energy used =1 × 10³W × 86400
- Energy used = 86400000J = 86.4 ×
W = 86.4MJ
The question requested the answer in 2 significant figures and the answer is 86MJ
Answer:
no
Explanation:
this is because its valency shell is full so it wont want any other electrons in its valence shell.
It’s will be B because the circuit had a open or close so if that doesn’t work than it’s because it’s open
Answer:
a) 4.9 s
b) 167.8 m
Explanation:
Hello!
To solve this question we need to make use of the equations of motion of both the motorcycle xm(t) and the car xc(t) at t=5
Let us consider the position of the motorcycle at t=5 as the origin, that is:
xm(t+5) = vt + (1/2)at^2
xc(t+5) = vt + 60 m
where v = 22.0m/s and a=5m/s^2
We are looking for the time t' when the position of the car and the motorcycle are the same:
xm(t'+5)=xc(t'+5)
vt' + (1/2)at'^2 = vt' +60m
t' = √(120 m /a) = 4.89898... s
Since we are considering the origin of the cooordinate system at the position when the motorcycle starts to accelerate, the distance travelled by the motorcycle until it catches the car is given by:
xm(t'+5)= vt' + (1/2)at'^2
xm(9.89898s) = (22 * 9.89898 + 2.5 * 9.89898^2)m
xm(9.89898s)= 167.777... m
This cab be solve using Newtons second law of motion :
F = ma
Where F is the force applied
A is the accelaration = v/s
V is the velosity
S is the time
M is the mass
F = (2100 kg)*( 96km/hr)( 1000m/ 1km)( 1 hr/3600 s) / 3.5 s
F = 16000 N is the force applied
