- Angle (θ) = 60°
- Force (F) = 20 N
- Distance (s) = 200 m
- Therefore, work done
- = Fs Cos θ
- = (20 × 200 × Cos 60°) J
- = (20 × 200 × 1/2) J
- = (20 × 100) J
- = 2000 J
<u>Answer</u><u>:</u>
<u>2</u><u>0</u><u>0</u><u>0</u><u> </u><u>J</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.

Explanation:
The acceleration due to gravity g is defined as

and solving for R, we find that

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration
experienced by the satellite is equal to the gravitational force
or

The orbital velocity <em>v</em> is the velocity of the satellite around the planet defined as

where <em>r</em><em> </em>is the radius of the satellite's orbit in meters and <em>T</em> is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

Solving for <em>M</em>, we get

Putting this expression back into Eqn(1), we get




Answer:
True
The escape speed from the Moon is much smaller than from Earth.
Explanation:
The escape speed is defined as:
(1)
Where G is the gravitational constant, M is the mass and r is the radius.
The mass of the Earth is
and its radius is 
Then, replacing those values in equation 1 it is gotten.
For the case of the Moon:
Hence, the escape speed from the Moon is much smaller than from Earth.
Since it has a smaller mass and smaller radius compared to that from the Earth.
I’m pretty sure it’s average speed= total distance and total time which is A.