Answer:
11.74
Explanation:
The formula to find the pH of a solution is..
pH = -log [H⁺]
pH = -log [1.8×10¹²]
pH = 11.74
The answer would be to 2 decimal places because the concentration is two significant digits.
The order of the solutions from lowest to highest concentration : A, B, C
<h3>Further explanation</h3>
Given
the following solutions
Required
order of increasing concentration
Solution
Molarity shows the number of moles of solute in every 1 liter of solution.

Solution A : 0.5 moles : 2 L solution = 0.25 M
Solution B : 1 moles : 3 L solution = 0.33 M
Solution C : 1.5 moles : 4 L solution = 0.375 M
Answer:
Explanation:
In electrophilic aromatic substitution, the substituent(s) that favors electrophilic attack is said to be ortho or para to the substituent. Meta directors are deactivators. Altogether, these directors have an integral role to play in the success and regioselectivity of electrophilic aromatic substitution reactions.
From the information given: The;
Strongly deactivating meta- director ⇒ NO₂ (nitro group)
Moderately deactivating meta- director ⇒ CN (cyano group)
Strongly activating ortho-/para- director ⇒ OH (hydroxy; group)
Weakly deactivating ortho-/para- director ⇒ -X (halide group)
Weakly activating ortho-/para- director ⇒ - Ph (phenyl group)
Answer:
PH= 2.54
Explanation:
Because the procedure involves many steps for its resolution and it works faster on paper and pencil, the detailed solution of this exercise is attached as a scanned image of the procedure for review.
In the procedure, the initial values of the problem and the replacement of these values with the correct formulas for this process are taken into account.
Answer: A.
and 
Explanation:
Galvanic cell is a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.
The standard reduction potential for aluminium and gold are as follows:


Reduction takes place easily if the standard reduction potential is higher (positive) and oxidation takes place easily if the standard reduction potential is less (more negative).
Here Al undergoes oxidation by loss of electrons, thus act as anode. Gold undergoes reduction by gain of electrons and thus act as cathode.
Anode : 
Cathode : 
Thus magnesium gets oxidized.