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2 years ago

You should have at least a ___ mph speed advantage when passing another vehicle

1 answer:

Studentka2010 [4]2 years ago

3 0

A driver should have at least a <u>10 mph</u> speed advantage when overtaking (passing) another vehicle.

<h3>What is a speed limit?</h3>

A speed limit refers to the maximum amount of speed that is legally permitted or allowed in a specific area for safety. Thus, this limit must be abided and strictly adhered to by all road users such as drivers of a vehicle.

According to the highway traffic code and regulations, a driver should have at least a <u>10 mph</u> speed advantage when overtaking (passing) another vehicle.

Read more on safety here: brainly.com/question/14751268

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You might be interested in

What issues does society try to forget in order to not have to deal with them ?

velikii [3]

Answer: Homelessness, Drug addiction, Mental Illness, Climate change.

Explanation:

Society would rather be ignorant to/ ignore all of these realities so they do not have to stop specific behaviors or actually acknowledge other people and help. Sometimes people are so stressed out about their own lives, they can not bare another persons issues. People are ignorant to climate change because correcting it requires massive changes and society is selfish and unwilling to change.

6 0

3 years ago

Two balanced Y-connected loads in parallel, one drawing 15kW at 0.6 power factor lagging and the other drawing 10kVA at 0.8 powe

NemiM [27]

Answer:

(a) attached below

(b) $pf_{C}=0.85$ $lagging$

(d) $X_{C} =49.37$ Ω

(e) $I_{cap} =9.72 A$ and $I_{line} =27.66 A$

Explanation:

Given data:

$P_{1}=15 kW$

$S_{2} =10 kVA$

$pf_{1} =0.6$ $lagging$

$pf_{2}=0.8$ $leading$

$V=480$ $Volts$

(a) Draw the power triangle for each load and for the combined load.

$\alpha_{1}=cos^{-1} (0.6)=53.13$ °

$\alpha_{2}=cos^{-1} (0.8)=36.86$ °

$S_{1}=P_{1} /pf_{1} =15/0.6=25 kVA$

$Q_{1}=P_{1} tan(\alpha_{1} )=15*tan(53.13)=19.99$ ≅ $20kVAR$

$P_{2} =S_{2}*pf_{2} =10*0.8=8 kW$

$Q_{2} =P_{2} tan(\alpha_{2} )=8*tan(-36.86)=-5.99$ ≅ $-6 kVAR$

The negative sign means that the load 2 is providing reactive power rather than consuming

Then the combined load will be

$P_{c} =P_{1} +P_{2} =15+8=23 kW$

$Q_{c} =Q_{1} +Q_{2} =20-6=14 kVAR$

(b) Determine the power factor of the combined load and state whether lagging or leading.

$S_{c} =P_{c} +jQ_{c} =23+14j$

or in the polar form

$S_{c} =26.92$ °

$pf_{C}=cos(31.32) =0.85$ $lagging$

The relationship between Apparent power S and Current I is

$S=VI^{*}$

Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.

Current of the combined load can be found by

$I_{C} =S_{C}/\sqrt{3}*V$

$I_{C} =26.92*10^3/\sqrt{3}*480=32.37 A$

(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω

$Q_{C} =3*V^2/X_{C}$

$X_{C} =3*V^2/Q_{C}$

$X_{C} =3*(480)^2/14*10^3$ Ω

(e) Compute the magnitude of the current in each capacitor and the line current from the source.

Current flowing in the capacitor is

$I_{cap} =V/X_{C} =480/49.37=9.72 A$

Line current flowing from the source is

$I_{line} =P_{C} /3*V=23*10^3/3*480=27.66 A$

8 0

3 years ago

How to make a shopping cart move with ease without a motor. Like if the carts front wheels were smaller than the ones in the bac

Anastasy [175]

Answer:give the cart another shape

Explanation:an aeroplane shape makes it fast,,in physical science,the streamlined body makes a body fast

3 0

4 years ago

Oil with a kinematic viscosity of 4 10 6 m2 /s fl ows through a smooth pipe 12 cm in diameter at 2.3 m/s. What velocity should w

Setler79 [48]

Answer:

Velocity of 5 cm diameter pipe is 1.38 m/s

Explanation:

Use following equation of Relation between the Reynolds numbers of both pipes

$Re_{5}$ = $Re_{12}$

$\sqrt{\frac{V_{5}XD_{5} }{v_{5}}}$ = $\sqrt{\frac{V_{12}XD_{12} }{v_{12}}}$

$Re_{5}$ = Reynold number of water pipe

$Re_{12}$ = Reynold number of oil pipe

$V_{5}$ = Velocity of water 5 diameter pipe = ?

$V_{12}$ = Velocity of oil 12 diameter pipe = 2.30

$v_{5}$ = Kinetic Viscosity of water = 1 x $10^{-6}$ $m^{2}$ /s

$v_{12}$ = Kinetic Viscosity of oil = 4 x $10^{-6}$ $m^{2}$ /s

$D_{5}$ = Diameter of pipe used for water = 0.05 m

$D_{12}$ = Diameter of pipe used for oil = 0.12 m

Use the formula

$\sqrt{\frac{V_{5}XD_{5} }{v_{5}}}$ = $\sqrt{\frac{V_{12}XD_{12} }{v_{12}}}$

By Removing square rots on both sides

${\frac{V_{5}XD_{5} }{v_{5}}}$ = ${\frac{V_{12}XD_{12} }{v_{12}}}$

${V_{5}$ = ${\frac{V_{12}XD_{12} }{v_{12}XD_{5}\\}}$ x $v_{5}$

${V_{5}$ = [ (0.23 x 0.12m ) / (4 x $10^{-6}$ $m^{2}$ /s) x 0.05 ] 1 x $10^{-6}$ $m^{2}$ /s

${V_{5}$ = 1.38 m/s

4 0

4 years ago

A dc shunt generator rated at 85 kW produces a voltage of 280 V. The brush voltage drop is 2.5 V, and the armature and field res

dalvyx [7]

Answer:

(a) Calculate the field, armature, and load currents versus load = 306A

(b) Determine the terminal voltage at no-load and at rated load conditions = 300V

(d) Plot the terminal voltage as a function of the load. Determine the load that corresponds to a 5% voltage drop using the no-load voltage as the base = 294.74V

Explanation:

CHECK THE ATTACHED FILES FOR DETAILED EXPLANATION.

3 0

3 years ago