Answer:
a) 93.852 kN
b) 128.043 mm
Explanation:
Stress is load over section:
σ = P / A
If plastic deformation begins with a stress of 297 MPa, the maximum load before plastic deformation will be:
P = σ * A
316 mm^2 = 3.16*10^-4
P = 297*10^6 * 3.16*10^-4 = 93852 N = 93.852 kN
The stiffness of the specimen is:
k = E * A / l
k = 113*10^9 * 3.16*10^-4 / 0.128 = 279 MN/m
Hooke's law:
x' = x0 * (1 + P/k)
x' = 0.128 * (1 + 93.852*10^3 / 279*10^6) = 0.128043 m = 128.043 mm
The answer is because the positive goes with the positive
Answer: Combustion of Hydrocarbons
Explanation:
The Independent variable in an experiment is the one whose effect on the dependent variable is being measured. The independent variable therefore is controlled to see the effect it will have in the experiment.
In this experiment, the scientists combusted different types of hydrocarbons (diesel, gasoline, natural gas and a gasoline/ethanol mixture) as they aimed to find out the effect that this burning would have on the environment thereby making the combustion of hydrocarbons the independent variable.
Answer:
Area of Circle = 78.5398
Surface Area of Sphere = 1.2566 x 10^3 = 1256.6 ft
Volume of Sphere = 33.5103 ft
Explanation:
Please find below the written MatLab script used to solve the problem. I had to define r in each case to solve for the Area of the circle, the surface area and the volume of the Sphere.
r=5; % define r as 5
a=pi*r^2;% calculate the area of the circle
AreaOfCircle=a
r=10; % define r and 10 ft
sa=4*pi*r^2; %Calculate the surface area of the sphere
SphereSurfaceArea=sa
r=2;% define r as 2 ft
vs=(4/3)*pi*r^3;% Calculate the volume of the sphere
VolumeShere=vs
Power tools are usually run on one of the three types of power: Compressed air, electricity, or combustion
