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3 years ago

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Tool life testing on a lathe under dry cutting conditions gauge 'n' and 'C' of Taylor tool life equation as 0.12 and 130 m/min.

respectively. When a coolant was used, 'C' increased by 10%. The increased tool life with the use of coolant at a cutting speed of 90 m/min is

1 answer:

Tom [10]3 years ago

7 0

Answer:

So % increment in tool life is equal to 4640 %.

Explanation:

Initially n=0.12 ,V=130 m/min

Finally C increased by 10% , V=90 m/min

Let's take the tool life initial condition is $T_1$ and when C is increased it become $T_2$ .

As we know that tool life equation for tool

$VT^n=C$

At initial condition $130\times (T_1)^{0.12}=C$ ------(1)

At final condition $90\times (T_2)^{0.12}=1.1C$ -----(2)

From above equation

$\dfrac{130\times (T_1)^{0.12}}{90\times (T_2)^{0.12}}=\dfrac{1}{1.1}$

$T_2=47.4T_1$

So increment in tool life = $\dfrac{T_2-T_1}{T_1}$

= $\dfrac{47.4T_1-T_1}{T_1}$

So % increment in tool life is equal to 4640 %.

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MissTica

Explanation:

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rows is initialized to 1 to ensure that row starts at 1 or you can remove it then seat number will start from 0.

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Code:

Please refer to the attached image.

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3 years ago

Find the mathematical equation for SF distribution and BM diagram for the beam shown in figure 1.

Novosadov [1.4K]

Answer:

i) SF: $v(x) = \frac{(w_0* x )^2}{2L}$

ii) BM : $= \frac{(w_0*x)^3}{6L}$

Explanation:

Let's take,

$\frac{y}{w_0} = \frac{x}{L}$

Making y the subject of formula, we have :

$y = \frac{x}{L} * w_0$

For shear force (SF), we have:

This is the area of the diagram.

$v(x) = \frac{1}{2} * y = \frac{1}{2} * \frac{x}{L} * w_0$

$= \frac{(w_0* x )^2}{2L}$

The shear force equation =

$v(x) = \frac{(w_0* x )^2}{2L}$

For bending moment (BM):

$BM = v(x) * \frac{x}{3}$

$= \frac{(w_0* x )^2}{2L} * \frac{x}{3}$

$= \frac{(w_0*x)^3}{6L}$

The bending moment equation =

$= \frac{(w_0*x)^3}{6L}$

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3 years ago

Select the correct answer.

Ulleksa [173]

The answer is A. Immediately inform her colleague

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3 years ago

1.8 A water flow of 4.5 slug/s at 60 F enters the condenser of steam turbine and leaves at 140 F. Determine the heat transfer ra

Ann [662]

Answer:

$Hr=4.2*10^7\ btu/hr$

Explanation:

From the question we are told that:

Water flow Rate $R=4.5slug/s=144.78ib/sec$

Initial Temperature $T_1=60 \textdegree F$

Final Temperature $T_2=140 \textdegree F$

Let

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And

$\triangle T= 140-60$

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3 years ago

The capacity of a battery is 1800 mAh and its OCV is 3.9 V. a) Two batteries are placed in series. What is the combined battery

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Answer:

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given data

battery = 1800 mAh

OCV = 3.9 V

solution

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capacity = 3600 mAh

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3 years ago