Answer:
See image and explanation
Explanation:
A simple pendulum consists of a string to which a bulb is attached and the string is tied to a support. The string swings from one end to the other as shown.
At the both ends, the energy of the pendulum is all potential. Hence we have 100J potential energy at both ends.
When the pendulum is in motion, the energy is all kinetic at the center of motion. Hence at that point, we have 100J kinetic energy.
In between both extremes the energy is both kinetic and potential as shown. The total energy is this a summation of the two.
Answer:
Required answer = 2.7 x 10^16 MOLECULES
Explanation:
We know that
1 m = 100 cm
so 1 m^3 = (100 cm)^3 = 1000000 cm^3 = 1 x 10^6 cm3
as per question, 2.7*10^{10} molecules in 1 cm^3
so number of molecules in 1 m^3
Number of molecules = ( 2.7 x 10^10 molecules /1 cm^3 ) x ( 1 x 10^6 cm3 / 1 m3)
Number of molecules = 2.7 x 10^10 x 1 x 10^6 = 2.7 x 10^16 per m3
Required answer = 2.7 x 10^16 MOLECULES
The answer is D
Explanation:
Answer:d
Explanation:
Drift velocity is given by
where 
=drift velocity
I=Current
n=no of electron
Q=charge of Electron
A=cross-section
If area of cross-section decreases gradually then drift velocity will increase because drift velocity is inversely proportional to Area of cross-section
Answer:
a) 2nd case rate of rotation gives the greater speed for the ball
b) 1534.98 m/s^2
c) 1515.04 m/s^2
Explanation:
(a) v = ωR
when R = 0.60, ω = 8.05×2π
v = 0.60×8.05×2π = 30.34 m/s
Now in 2nd case
when R = 0.90, ω = 6.53×2π
v = 0.90×6.53×2π = 36.92 m/s
6.35 rev/s gives greater speed for the ball.
(b) a = ω^2 R = (8.05×2π)^2 )(0.60) = 1534.98 m/s^2
(c) a = ω^2 R = (6.53×2π)^2 )(0.90) = 1515.05 m/s^2
