Answer:
The torque about the origin is 
Explanation:
Torque 
is the cross product between force 
and vector position 
respect a fixed point (in our case the origin):
There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:
![\overrightarrow{r}\times\overrightarrow{F} =-\left[\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k}\\ F1_{x} & F1_{y} & F1_{z}\\ r_{x} & r_{y} & r_{z}\end{array}\right]](https://tex.z-dn.net/?f=%20%5Coverrightarrow%7Br%7D%5Ctimes%5Coverrightarrow%7BF%7D%20%3D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Chat%7Bi%7D%20%26%20%5Chat%7Bj%7D%20%26%20%5Chat%7Bk%7D%5C%5C%20F1_%7Bx%7D%20%26%20F1_%7By%7D%20%26%20F1_%7Bz%7D%5C%5C%20r_%7Bx%7D%20%26%20r_%7By%7D%20%26%20r_%7Bz%7D%5Cend%7Barray%7D%5Cright%5D%20)
Answer: All isotopes of a given element have the same number of protons but different numbers of neutrons in each atom. ... Each atomic number identifies a specific element, but not the isotope; an atom of a given element may have a wide range in its number of neutrons.
Explanation: Hopefully this helps. Have a great day.
Answer:
Approximately 
(approximately 
) assuming that the magnetic field and the wire are both horizontal.
Explanation:
Let 
denote the angle between the wire and the magnetic field.
Let 
denote the magnitude of the magnetic field.
Let 
denote the length of the wire.
Let 
denote the current in this wire.
The magnetic force on the wire would be:
.
Because of the 
term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is 
.)
In this question:
(or, equivalently, 
radians, if the calculator is in radian mode.)
.
.
.
Rearrange the equation 
to find an expression for , the current in this wire.
.
Answer:
N = 167 Newtons
R = 727 Newtons
Explanation:
i) For static equilibrium, moments about any convenient point must sum to zero.
A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.
ii) I will <em>ASSUME </em>the two moment arms are 0.05m and 0.15 m
CCW moments about the fulcrum are
190 N(0.2 m) + 280 N(0.05 m) = 52 N•m
CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m
For static equilibrium, these must be equal
27 + 0.15N = 52
0.15N = 25
N = 166.6666666...
Sum moments about N to zero
(Same as saying CW and CCW moments must balance)
190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0
R = 726.6666666...
We could verify this by summing vertical forces to zero.
R - 190 - 280 - 166.666666 - 90 = 0
R = 726.6666666...
In my school, a student
who refuses to wear their uniform gets suspended.
<span>Our school is quite strict
when it comes to our uniform. If you get caught with your tie off, an undone
button or untucked shirt, you will get a 45-minute detention after school.
Sometimes, when a student doesn’t wear their school uniform and the security
guard or the discipline officer catches them, they may also be required to do
community service or have their ID confiscated. Most of the time, this is done
so a student would be a better person that follows the protocols set by an
institution, and this makes a student prepared for the real world, equipped
with good values.</span>
