I really need help with this question. This is for chemistry

Chemistry

1 answer:

chubhunter [2.5K]2 years ago

8 0

Answer:

B.) 33.5 mL

Explanation:

The density measurement can be used as a conversion. It allows you to go between grams and mL. When you say the density of mercury is 13.6 g/mL, you are technically saying that there are 13.6 grams of mercury per every 1 mL. So, if you want to convert between grams and mL, you need to multiply the staring amount by this conversion. Because you want to cancel out grams, you need to put this unit in the denominator of the ratio.

455 grams mercury 1 mL
------------------------------ x -------------------- = 33.5 mL mercury
13.6 grams

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zaharov [31]

Answer:

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Explanation:

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Answer:

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If the solubility of sugar at 25ºC is 211 g/100 g H2O, what mass of sugar can be dissolved in 300 g of H2O?

ladessa [460]

Answer:

633 grams of sugar can be dissolved in 300 g of H₂O

Explanation:

Solubility is the measure of the ability of a certain substance to dissolve in another and form a homogeneous system. Solubility is then the maximum amount of a solute that a solvent can receive and is expressed by concentration units.

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

Then:

$x=\frac{c*b}{a}$

You can apply the rule of three as follows: if by definition of solubility in 100 grams of H₂O there are 211 grams of sugar, in 300 g of H₂O how much sugar is there?

$sugar=\frac{300 grams of H_{2}O *211 grams of sugar}{100 grams of H_{2}O}$