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Dima020 [189]
2 years ago
9

A car travels 263.0 miles in 5.5 hours. How long will it take to travel 363.0 miles at

Physics
1 answer:
yan [13]2 years ago
5 0

From the average velocity calculated, if the car should travel 363.0 miles, the time elapsed will be 7.6 hours.

<h3>How long will it take to travel 363.0 miles at the given average velocity? </h3>

Note that; Velocity is the speed at which an object moves in a particular direction. It is expressed as;

v = distance / time

Given that;

  • Distance covered by the car d = 263.0 miles
  • Time elapsed t = 5.5 hours

First we determine the velocity of the car.

v = distance / time

v = 263.0 miles / 5.5 hours

v = 47.8181 miles per hour.

Now, if the car travels 363.0 miles, time elapsed will be;

velocity = distance / time

time = distance / velocity

time = 363.0 miles / 47.8181 miles per hour

time = 7.6 hours

Therefore, from the average velocity calculated, if the car should travel 363.0 miles, the time elapsed will be 7.6 hours.

Learn more about speed here: brainly.com/question/7359669

#SPJ1

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The half-life of the radioactive element beryllium-13 is 5 × 10-10 seconds, and half-life of the radioactive element beryllium-1
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<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>

Explanation:

The half-life h of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.

In this case, we are given the half life of two elements:

beryllium-13: h_{B-13}=5(10)^{-10}s=0.0000000005s

beryllium-15: h_{B-15}=2(10)^{-7}s=0.0000002s

As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?

We can find it out by the following expression:

h_{B-15}=X.h_{B-13}

Where X is the amount we want to find:

X=\frac{h_{B-15}}{h_{B-13}}

X=\frac{2(10)^{-7}s}{5(10)^{-10}s}

Finally:

X=400

Therefore:

The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.

8 0
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A stationary 6-kg shell explodes into three pieces. One 4.0 kg piece moves horizontally along the negative x-axis. The other two
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Answer:

-15 m/s

Explanation:

The computation of the velocity of the 4.0 kg fragment is shown below:

For this question, we use the correlation of the momentum along with horizontal x axis

Given that

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Other two fragments each = 1.0 kg

Angle = 60

Speed = 60 m/s

Based on the above information, the velocity = v is

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\frac{60}{2} + \frac{60}{2} - 4\ v = 0

v = \frac{60}{4}

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